Answer:
13807.2 J/g°C
Explanation:
I just took the test and got it correct
Answer:
a. 2.1 s
b.0.48 Hz
c. A=24cm
d. 72cm/s
Explanation:
An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 57.0 cm mark on the track. The glider completes 15.0 oscillations in 31.0 s.What are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider?
What are the period,
period is the time taken for a wave particle to make one complete oscillation
a) 31 / 15 = 2.066 seconds
= 2.1 s
(b) frequency
: this the number of oscillation made in one seconds.
it is also the inverse of the period.
= oscillations / time
= 15/31= 0.48 Hz
(c) amplitude
: maximum displacement from the origin
amplitude = 1/2 of the difference of oscillation marks
= 1/2(57-10) = 47/2cm
23.5cm
A=24cm
(d) maximum speed of the glider?
V=ωA
angular frequency *Amplitude
V=a*pi*f*amplitude
2π x frequency x amplitude = maximum speed
= 2π x .48 x 24
=72.38 cm/s
72cm/s
From the calculations, the speed of sound in this case is 16.9 m/s.
<h3>What is an echo?</h3>
The term echo has to do with the reflection of sound waves. Sound is a mechanical wave.
we know that the speed of sound is obtained from;
V = 2x/t
x = distance covered
t = time taken
V = 2(500)/59
v = 16.9 m/s
The error in the experiment could come from;
- Lack of precise time measurement
- Error can also arise from the environment of the experiment
Learn more about echo:brainly.com/question/9527413
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Answer:
Banked
Explanation:
Banked curves are formed when the inner edge is below the outer edge.
It is done in order to ensure the reliability of the frictional force as it varies when the road is wet wet or oily. Thus in order to avoid these problems the curved roads are banked.
Banking of the curve provides the necessary centripetal force, i.e., the horizontal component of the normal reaction force to keep the vehicle i motion and thus helps in reducing the effect of the forward motion force on the vehicle.
if for a force of 0.5 N we have a displacement of -0.02m we can calculate the elastic constant(k) with the formula F=-kx(F=0.5N x=-0.02)
k=F/x k=0.5/0.02=25N/m
now we can calculate the period by the formula
T=2π√(m/k)
in the mass we convert grams to kilograms so 100g=0.1kg
T=6.28√(0.1/25)⇒T=0.39seconds
