h = height of the beaker = 34 cm = 0.34 m
ρ = density of water in the beaker = 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
P₀ = atmospheric pressure = 101325 pa
P = pressure at the bottom of the beaker
Pressure at the bottom of the beaker is given as
P = P₀ + ρ g h
inserting the values
P = 101325 + (1000) (9.8) (0.34)
P = 104657 Pa
d = diameter of cylindrical beaker = 6 cm = 0.06 m
A = area of the bottom of the beaker = (0.25)πd² = (0.25) (3.14) (0.06)² = 0.00283 m²
Downward force of the water on the bottom of the beaker is given as
F = PA
F = (104657) (0.00283)
F = 296.2 N
