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cestrela7 [59]
3 years ago
5

A 34-cm-tall, 6.0-cm-diameter cylindrical beaker is filled to its brim with water.What is the downward force of the water on the

bottom of the beaker?
Physics
1 answer:
Solnce55 [7]3 years ago
3 0

h = height of the beaker = 34 cm = 0.34 m

ρ = density of water in the beaker = 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

P₀ = atmospheric pressure = 101325 pa

P = pressure at the bottom of the beaker

Pressure at the bottom of the beaker is given as

P = P₀ + ρ g h

inserting the values

P = 101325 + (1000) (9.8) (0.34)

P = 104657 Pa

d = diameter of cylindrical beaker = 6 cm = 0.06 m

A = area of the bottom of the beaker = (0.25)πd² = (0.25) (3.14) (0.06)² = 0.00283 m²

Downward force of the water on the bottom of the beaker is given as

F = PA

F = (104657) (0.00283)

F = 296.2 N

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b) To find the distance traveled by the baseball first we need to find the time of flight:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

0 = 1 m + 32.5m/s*sin(45)t - \frac{1}{2}9.81 m/s^{2}t^{2}

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Hence, the total distance traveled by the baseball was 108.7 m.

I hope it helps you!                                                                                  

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