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ladessa [460]
3 years ago
11

. A 0.100 M solution of the weak acid HA was titrated with 0.100 M NaOH. The pH measured when Vb = ½Ve was 4.62. Using activity

coefficients, calculate pKa. The size of the A- anion is 450 pm.
Chemistry
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

pk_a = 4.69

Explanation:

V_b = \frac{1}{2} V_e

pk_a(c) = 4.62\\pk_a(c) = - logk_a(c)\\4.62 = - logk_a(c)\\k_a(c) = antilog (-4.62)\\k_a(c) = 2.4 * 10^{-65}

Activity coefficients:

f_A = 0.854\\f_H = 1.00\\f_{HA} = 1.00

k_a = k_a(c) *f_A* \frac{f_H}{f_{HA}} \\k_a = 2.4 * 10^{-5} *0.854* \frac{1.0}{1.0}\\k_a = 2.05 * 10^{-5}

pk_a = -log(k_a)\\pk_a = -log(2.05*10^{-5})\\pk_a = 4.69

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