O2 gas, where there are two Oxygen atoms which are covalently bonded together
Answer:
- Empirical:
![C_3H_7](https://tex.z-dn.net/?f=C_3H_7)
- Molecular:
![C_6H_{14}](https://tex.z-dn.net/?f=C_6H_%7B14%7D)
Explanation:
Hello,
In this case, based on the information regarding the combustion, the moles of carbon turn out:
![n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC](https://tex.z-dn.net/?f=n_C%3D21.71gCO_2%2A%5Cfrac%7B1molCO_2%7D%7B44gCO_2%7D%2A%5Cfrac%7B1molC%7D%7B1molCO_2%7D%3D0.493molC)
Moreover, the moles of hydrogen:
![n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH](https://tex.z-dn.net/?f=n_H%3D10.37gH_2O%2A%5Cfrac%7B1molH_2O%7D%7B18gH_2O%7D%2A%5Cfrac%7B2molH%7D%7B1molH_2O%7D%3D1.152molH)
Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:
![C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B0.4934%7D%7B0.4934%7D%3D1%5C%5CH%3D%5Cfrac%7B1.15222%7D%7B0.4934%7D%3D2.335%5C%5CCH_%7B2.335%7D)
Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:
![C_3H_7](https://tex.z-dn.net/?f=C_3H_7)
In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:
![C_6H_{14}](https://tex.z-dn.net/?f=C_6H_%7B14%7D)
Which is hexane.
Best regards.
The question ask to predict the effect where as coal can be used to generate hydrogen gas by this endothermic reason and the best answer among your choices based on the element you give is letter C. raising the temperature of the reaction mixture. I hope my answer is correct
Answer:
deposition
Explanation:
Sublmation- solid transforming into a gas, skipping the liquid stage.
eveporation- a liquid transformimg into a gas
melting- a solid transforming into a liquid
deposition- the opposite of sublimation (your anwser)