Each station can detect how far away the epicenter was. So each station basically has a circle made of possible epicenters. When you have three, you narrow it down to one, final point.
a) It is absolute, so it does not change.
b) Inertial ones.
c) Inside the train the time will slow down relatively to the outside clock. So if one travel at nearly the speed if light for 2 hours on his clock, for outdoor observers it will look like 3 hours.
Please ignore my comment -- mass is not needed, here is how to solve it. pls do the math
at bottom box has only kinetic energy
ke = (1/2)mv^2
v = initial velocity
moving up until rest work done = Fs
F = kinetic fiction force = uN = umg x cos(a)
s = distance travel = h/sin(a)
h = height at top
a = slope angle
u = kinetic fiction
work = Fs = umgh x cot(a)
ke = work (use all ke to do work)
(1/2)mv^2 = umgh x cot(a)
u = (1/2)v^2 x tan (a) / gh
Answer:
The object distance is 92 cm.
Explanation:
let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.
then, the magification of the mirror is given by:
m = -v/u and m = h/H
so, -v/u = h/H
u = -v×H/h
= -(-4.6)×(82)/(4.1)
= 92 cm
Therefore, the object distance is 92 cm.
Oooooooooooooooooooooooooooooooooooo
