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inessss [21]
3 years ago
7

What volume(in dm³) of 0.30 moldm-³ Nacl solution can be prepared from 0.060mol of solute?​

Chemistry
1 answer:
Ivanshal [37]3 years ago
7 0

Answer:

0.2 dm³

Explanation:

Concentration = no. of moles of solute / volume

Concentration: 0.30 mol dm-³

no. of moles of solute: 0.060mol

0.3 = 0.06 / v

v = 0.2 dm³

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How many moles are in 1.20 times 10^25 atoms of phosphorus
Stels [109]

19.927 moles are in 1.20 times 10^{25} atoms of phosphorus.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 ×10^{23} of some chemical unit, be it atoms, molecules, ions, or others.

1 mole of any substance contain Avogadro's number of molecules so we can calculate the number of moles by dividing the provided number of atoms over Avogadro's number to obtain the number of moles .

Moles= \frac{Atoms}{\;Avogadro's \;number }

Moles=  1.20 X 10^{25} atoms ÷ 6.022 X 10^{23}

= 19.927

Hence, 19.927 moles are in 1.20 times 10^{25} atoms of phosphorus.

Learn more about moles here:

brainly.com/question/26416088

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5 0
2 years ago
Which system includes feet, pounds, gallons, and miles?<br><br> metric <br><br> customary
slavikrds [6]

Answer:

customary Is the required system

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EXPLAIN How did energy change form in the calorimeter lab?
timama [110]

Answer:

Chemical energy is converted into thermal and mechanical energy while kinetic energy into potential energy.

Explanation:

As the breakdown of food started, the chemical energy present in the food substances converted into thermal energy and mechanical energy. Thermal or heat energy is used to maintain the body's temperature while mechanical energy is used in other activities such as movement of muscles. Kinetic energy is also converted into potential energy when the object moves from top of a place such as hill.

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5 0
3 years ago
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An unknown gas effuses at one half the speed of oxygen. What is the molar mass of the unknown? It is either HBr or HI. Which gas
sertanlavr [38]

Answer:

HI.

Explanation:

  • Thomas Graham found that, at a constant  temperature and pressure the rates of effusion  of various gases are inversely proportional to  the square root of their masses.

Rate of effusion ∝ 1/√molar mass.

  • <em>(Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).</em>
  • An unknown gas effuses at one half the speed of that of oxygen.

∵ Rate of effusion of unknown gas = 1/2 (Rate of effusion of O₂)

∴ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = 2.

Molar mass of O₂ = 32.0 g/mol.

∵ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).

∴  2.0 = (√molar mass of unknown gas) / √32.0.

( √molar mass of unknown gas) = 2.0 x √32.0

By squaring the both sides:

∴ molar mass of unknown gas = (2.0 x √32.0)² = 128 g/mol.

∴ The molar mass of sulfur dioxide = 80.91 g/mol and the molar mass of HI = 127.911 g/mol.

<em>So, the unknown gas is HI.</em>

<em></em>

5 0
3 years ago
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