Answer:
Explanation:
You need to remember that the oxidation number of H is +1, except when it is in a metal hydrites like NaH, where its oxidation number is -1. Then, the oxidation number of O is -2, but in peroxides is -1. So with these rules you just have to multiply the ox. number with the name of atoms and all the elements in the reaction must sum 0.
My educated guess should be the 3rd one
The General Equation of Alkane is as follow,
CnH₂n₊₂ ------- (1)
As m/z = 380
So,
CnH₂n₊₂ = 380
Or,
12n+ 1₂n₊₂ = 380
12n+ ₂n ₊ ₂ = 380
14n ₊ ₂ = 380
14n = 380 - 2
14n = 378
n = 378 / 14
n = 27
Now, putting value of n in eq. 1
C₂₇H₍₂₇ₓ₂₎₊₂
C₂₇H₅₆
Result:
n = C = 27
y = H = 56