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RideAnS [48]
3 years ago
12

What are the industrial conditions used in the Haber process and why?

Chemistry
1 answer:
laila [671]3 years ago
5 0
About 450*C, a pressure of about 200atm and a catalyst or iron
You might be interested in
How can you determine which bond in a structure is more polar without using an electronegativity table?
UkoKoshka [18]
To know this you pretty much do have to kind of memorize a few electronegativities. I don't recall ever getting a table of electronegativities on an exam.
From the structure, you have:

I remember the following electronegativities most because they are fairly patterned:
EN
H
=
2.1
EN
C
=
2.5
EN
N
=
3.0
EN
O
=
3.5
EN
F
=
4.0
EN
Cl
=
3.5
Notice how carbon through fluorine go in increments of
~
0.5
. I believe Pauling made it that way when he determined electronegativities in the '30s.
Δ
EN
C
−
Cl
=
1.0
Δ
EN
C
−
H
=
0.4
Δ
EN
C
−
C
=
0.0
Δ
EN
C
−
O
=
1.0
Δ
EN
O
−
H
=
1.4
So naturally, with the greatest electronegativity difference of
4.0
−
2.5
=
1.5
, the
C
−
F
bond is most polar, i.e. that bond's electron distribution is the most drawn towards the more electronegative compound as compared to the rest.
When the electron distribution is polarized and drawn towards a more electronegative atom, the less electronegative atom has to move inwards because its nucleus was previously favorably attracted to the electrons from the other atom.
That means generally, the greater the electronegativity difference between two atoms is, the shorter you can expect the bond to be, insofar as the electronegative atom is the same size as another comparable electronegative atom.
However, examining actual data, we would see that on average, in conditions without other bond polarizations occuring:
r
C
−
Cl
≈
177 pm
r
C
−
C
≈
154 pm
r
C
−
O
≈
143 pm
r
C
−
F
≈
135 pm
r
C
−
H
≈
109 pm
r
O
−
H
≈
96 pm
So it is not necessarily the least electronegativity difference that gives the longest bond.
Therefore, you cannot simply consider electronegativity. Examining the radii of the atoms, you should notice that chlorine is the biggest atom in the compound.
r
Cl
≈
79 pm
r
C
≈
70 pm
r
H
≈
53 pm
r
O
≈
60 pm
So assuming the answer is truly
C
−
C
, what would have to hold true is that:
The
C
−
F
bond polarization makes the carbon more electropositive (which is true).
The now more electropositive carbon wishes to attract bonding pairs from chlorine closer, thereby shortening the
C
−
Cl
bond, and potentially the
C
−
H
bond (which is probably true).
The shortening of the
C
−
Cl
bond is somehow enough to be shorter than the
C
−
C
bond (this is debatable).
5 0
4 years ago
Read 2 more answers
As you move left to right across a period, which of the following always increases?
Artist 52 [7]

Answer:

she'll number

Explanation:

cause thats the only one

7 0
4 years ago
Read 2 more answers
Write me a brief description of a Nerve Signal. (Only one sentence)
astraxan [27]

Description of a nerve signal

The nerve signal, or action potential, is a coordinated movement of sodium and potassium ions across the nerve cell membrane. Here's how it works: As we discussed, the inside of the cell is slightly negatively charged (resting membrane potential of -70 to -80 mV).

7 0
3 years ago
Nickel (II) oxide reacts with carbon monoxide to form nickel metal. CO(g) + NiO(s) ⇄ CO2(g) + Ni(s) Kp = 20 at 873 K If a reacti
ozzi

Answer:

Explanation:

Hello,

Based on the statement of the equilibrium law:

Kp=\frac{P_{CO_2}^{EQ}}{P_{CO}^{EQ}}

By increasing (doubling) the amount of carbon monoxide, the production of nickel will increase since its amount is directly proportional with its pressure, so, by adding more reactant (in this case carbon monoxide), the equilibrium is rightward shifted based on Le Châtelier's principle even when solid either reactants or products are not contemplated in the equilibrium law.

Best regards.

4 0
3 years ago
To which third period element do these ionization values belong?
aleksklad [387]

IE1 = 578 kJ/mol 


IE2 = 1820 kJ/mol 


IE3 = 2750 kJ/mol 


IE4 = 11600 kJ/mol


If the following set of successive ionization energies are your ionization values this would likely belong to Aluminum. Since there is a huge point between the third and fourth ionization energies, which designates that the atom reached noble gas configuration after the third electron was removed. The element which has 3 valence electrons in the third period is aluminum.

4 0
3 years ago
Read 2 more answers
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