Describe the relationship between the pressure and volume of a gas when temperature and mass are constant
1 answer:
Answer:
The product of Pressure and Volume is a constant.
Explanation:
We know the Ideal gas equation,
PV = nRT,
where,
P - Pressure of the gas
V - Volume of the gas
n - No. of moles of the gas taken
R - Universal Gas Constant.
T - Temperature of the gas.
We know that , n =
where, wt - Mass of gass ; Mwt - Molecular weight of the gas.
We are given the weight of the gas remains constant (wt is a constant)
Therefore as n = ,(where both wt and Mwt are constants)
n is a constant in this process.
Universal gas constant is a constant
Given temperature is a constant.
Therefore,
As, PV = nRT, (where n,R,T are constants),
PV is a constant.
Therefore we can say,
PV = k, for some constant k.
If we plot a graph for P vs V , we get a Rectangular Hyperbola( One of the general forms of a Rectangular Hyperbola is xy = c)
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Answer:
Let's start by considering the ideal gas law:
where
p is the gas pressure
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature
This equation can also be rewritten as
Now, if we consider a fixed amount of gas, this means that the number of moles (n) is constant. So we can rewrite the equation as
And therefore, if we consider a gas undergoing a certain transformation from 1 to 2, we can write
where 1 indicates the conditions of the gas at the beginning and 2 the conditions of the gas after the process. So, the change in pressure/temperature/volume of the gas can be found by using this equation.
Answer:
the ball experiences the greater momentum change
Explanation:
You have to take into account that momentum change is given by
where vf and vb are the speed of the object after and before the impact.
In the case of the ball you have
where the minus of vf is included due to the motion is in an opposite direction regarding with vb
And for the lump
Hence, the ball experiences the greater change
hope this helps!!