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avanturin [10]
2 years ago
6

Can someone please help me because this is a hard problem to solve.

Physics
1 answer:
ivolga24 [154]2 years ago
7 0

Answer:

25.0 m / 10 m/s = 2.5 s

50.0 / 9.5 = 5.26 s

25.0 / 11.1 = 2.25 s

T (Wood) = 2.5 + 5.26 + 2.25 = 10.0 s

Mrs Wood runs 10 s vs 10.4 for Mr Overstreet

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Answer:

The time needed is T  = 16.8 s

Explanation:

From the question we are told that

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Generally the force acting on the spaceship is  

       F  =  ma

Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so

      F  = \frac{mv^2}{r}

Thus  

       ma  =  \frac{mv^2}{r}

=>    \frac{v^2}{r}  =  a

      Generally the speed of this spaceship is mathematically represented as

      v =  \frac{2 \pi}{T}

=>    v^2  =   [\frac{2\pi}{T}] ^2

=>     \frac{\frac{4\pi^2 r^2}{T^2} }{r}  = 0.5g

=>       \frac{4 \pi^2 r }{T^2} =  0.5 g

=>         T  = \sqrt{ \frac{4\pi^2 r}{0.5g}}

substituting values

          T  = \sqrt{ \frac{4* (3.142)^2 *(35)}{0.5 * 9.8}}

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Answer:

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The arc length is 1 m, so the angle is:

s = rθ

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Use constant acceleration equation to find ω.

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