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Tema [17]
2 years ago
10

Waves : Transfer of Energy

Physics
1 answer:
garri49 [273]2 years ago
7 0

✒ Answer

In the case of still lake and ocean water how are they different in transferring energy from one location to another?

  • Answer:Energy is transferred in waves through the vibration of particles

In what direction will you move a rope to create transverse waves?

  • Answer: in the direction of the black arrow

In what direction will you move a slinky to create longitudinal waves?

  • Answer: parallel to the direction that energy is transported.

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Which scientific law is also known as the law of inertia? PLZ HELP ASAPPPPPPPPP!!!
Flauer [41]

Answer:

Newton's First Law of Motion

Explanation:

Without external forces acting on an object, the object tends to move at constant speed in a straight line. This property is referred to as inertia. Newton's first law states this natural observation.

4 0
3 years ago
Read 2 more answers
Two loudspeakers are placed on a wall 2 m apart. A listener stands directly in front of one of the speakers, 81.7 m from the wal
OverLord2011 [107]

Answer:

The phase difference is       \Delta \phi = 1.9995 rad  

Explanation:

From the question we are told that

    The distance between the  loudspeakers is d = 2m

     The distance of the listener from the wall  D = 81.7 \ m

     The frequency of the  loudspeakers is  f = 4450Hz

      The velocity of sound is v_s = 343 m/s

     

The path difference of the sound wave that is getting to the listener is mathematically represented as

        \Delta z  =\sqrt{d^2 + D^2} -D

Substituting values

        \Delta z  =\sqrt{2^2 + 81.7^2 } -81.7

       \Delta z  =0.0245m

The phase difference is mathematically represented as

           \Delta \phi =  \frac{2 \pi}{\lambda } *  \Delta z

Where \lambda is the wavelength which is mathematically represented as

          \lambda  = \frac{v_s }{f}

substituting value  

          \lambda  = \frac{343 }{4450}

        \lambda  = 0.0770 m

Substituting value into the  equation for phase difference

      \Delta \phi =  \frac{2 * 3.142 * 0.0245}{0.0770}

      \Delta \phi = 1.9995 rad  

8 0
3 years ago
Can someone help me with any of these problems or all of them? It will get you an easy ten points per question
MrRa [10]

Answer: For number 9, the children would not be able to close the box.

Explanation: The combined force of the children is 55 N. The box spring overpowers them with 60 N. I hope this helps!

6 0
3 years ago
What is the relationship between gravity and electromagatism?
Mashcka [7]
Gravitational forece can only attract whereas electomagatism can be attractive and repulsive
5 0
3 years ago
An object is placed in front of a convex lens of a length 10cm. What is the nature of the image formed if the object distance is
Lady_Fox [76]

{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\

\:\:\:\:\bullet\:\:\:\sf{Focal\:length=10\:cm}

\:\:\:\:\bullet\:\:\:\sf{Object \ distance = -15\:cm}

\\

{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\

\:\:\:\:\bullet\:\:\:\sf{Nature \: of \:the\:image}

\\

{\mathfrak{\underline{\purple{\:\:\: Solution:-\:\:\:}}}} \\ \\

<h3>☯ <u>By using formula of Lens</u> </h3>

\\

\dashrightarrow\:\: {\boxed{\sf{\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}}}}

\\

\dashrightarrow\:\: \sf{\dfrac{1}{v}-\dfrac{1}{-15}=\dfrac{1}{10}}

\\

\dashrightarrow\:\: \sf{\dfrac{1}{v}+\dfrac{1}{15}=\dfrac{1}{10}}

\\

\dashrightarrow\:\: \sf{\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{15}}

\\

\dashrightarrow\:\: \sf{\dfrac{1}{v} = \dfrac{1}{30}}

\\

\dashrightarrow\:\: \sf{ v = 30 \ cm}

\\

<h3>☯ <u>Now, Finding the magnification </u></h3>

\\

\dashrightarrow\:\: \sf{ m = \dfrac{-30}{-15}}

\\

\dashrightarrow\:\: \sf{m = -2}

\\

<h3>☯ <u>Hence</u>,\\</h3>

\:\:\:\:\star\:\:\:\sf{Image \ distance = 30 \ cm}

\:\:\:\:\star\:\:\:\sf{Nature = Real \ \& \ inverted}

3 0
3 years ago
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