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HACTEHA [7]
3 years ago
6

A football player attempts a 30‐yd field goal. If he is able to impart a velocity u of 100 ft/sec to the ball, compute the minim

um angle θ. for which the ball will clear the crossbar of the goal. (Hint: Let m = tan θ)
Engineering
1 answer:
ki77a [65]3 years ago
4 0

Answer:2.53°

Explanation:The ball is undergoing a projectile motion that is why it has an angle

Range = (U^2 sin2a)/g

U= velocity of the ball=100ft/sec

Range of the ball(i.e horizontal distance the ball crossed)= 30yard=90ft

a=angle the ball is projected

g= acceleration due to gravity=9.8m/s^2

90=(100^2×sin2a)/9.8

90×9.8=10000×sin2a

882/10000=sin2a

0.0882=sin2a

Sin^-1 0.0882=2a

5.06=2a

a=5.06/2

a=2.53

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The theoretical maximum specific gravity of a mix at 5.0% binder content is 2.495. Using a binder specific gravity of 1.0, find
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The theoretical maximum specific gravity at 6.5% binder content is 2.44.

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Given the specific gravity at 5.0 %  binder content 2.495

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