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HACTEHA [7]
3 years ago
6

A football player attempts a 30‐yd field goal. If he is able to impart a velocity u of 100 ft/sec to the ball, compute the minim

um angle θ. for which the ball will clear the crossbar of the goal. (Hint: Let m = tan θ)
Engineering
1 answer:
ki77a [65]3 years ago
4 0

Answer:2.53°

Explanation:The ball is undergoing a projectile motion that is why it has an angle

Range = (U^2 sin2a)/g

U= velocity of the ball=100ft/sec

Range of the ball(i.e horizontal distance the ball crossed)= 30yard=90ft

a=angle the ball is projected

g= acceleration due to gravity=9.8m/s^2

90=(100^2×sin2a)/9.8

90×9.8=10000×sin2a

882/10000=sin2a

0.0882=sin2a

Sin^-1 0.0882=2a

5.06=2a

a=5.06/2

a=2.53

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What is the perimeter of 14-7 and 3-4
Goshia [24]

Answer:

If you mean two sides are 7 and two sides are 14 then you'd have 42

and for the second you'd have 14

Explanation:

7 + 7 = 14, 14 + 14 = 28, 14 + 28 = 42

3 + 3 = 6, 4 + 4 = 8, 8 + 6 = 14

5 0
3 years ago
A heat engine that rejects waste heat to a sink at 520 R has a thermal efficiency of 35 percent and a second- law efficiency of
xeze [42]

Answer:

The source temperature is 1248 R.

Explanation:

Second law efficiency of the engine is the ratio of actual efficiency to the maximum possible efficiency that is reversible efficiency.

Given:  

Temperature of the heat sink is 520 R.

Second law efficiency is 60%.

Actual thermal efficiency is 35%.

Calculation:  

Step1

Reversible efficiency is calculated as follows:

\eta_{II}=\frac{\eta_{a}}{\eta_{rev}}

0.6=\frac{0.35}{\eta_{rev}}

\eta_{rev}=0.5834

Step2

Source temperature is calculated as follows:

\eta_{rev}=1-\frac{T_{L}}{T}

\eta_{rev}=1-\frac{520}{T}

0.5834=1-\frac{520}{T}

T = 1248 R.

The heat engine is shown below:

Thus, the source temperature is 1248 R.

6 0
3 years ago
In order to test the reverse route back towards the original host, which of the following will you use? A Standard ping B Extend
Vlad1618 [11]

The function that you will use in order to test the reverse route back toward the original host is known as Extended ping. Thus, the correct option for this question is B.

<h3>What is Ping and traceroute for?</h3>

Ping and traceroute are the common commands you can effectively utilize in order to troubleshoot network problems. Ping is a simple command that can typically test the reachability of a device on the network. While traceroute is a command you use to 'trace' the route that a packet takes when traveling to its destination.

Extended ping permits a router's ping command to use The router's LAN IP address from within the subnet, fully testing the route back to the subnet. A standard ping often does not test the reverse route that you need to back toward the original host.

Therefore, the function that you will use in order to test the reverse route back toward the original host is known as Extended ping. Thus, the correct option for this question is B.

To learn more about Ping and traceroute, refer to the link:

brainly.com/question/28333920

#SPJ1

6 0
1 year ago
A. Imagine the white car in the left lane is moving more slowly than the surrounding traffic. How is this a violation of a state
asambeis [7]

The roads have pre-described lanes that should follow a particular speed and rules. When a driver drives slowly than he makes the other drivers impatient.

<h3>What are traffic rules?</h3>

Traffic rules are the regulations that are defined to regulate the vehicles and other conveyances that walk on the road. They are different in various places and have separate punishments for not following them.

The left lane of the road is generally for the drivers who want to pass by the vehicle ahead by following the mph rule. If the driver drives slowly then they make the other people impatient and result in honking.

Therefore, the driver driving slowly in the left lane makes others impatient.

Learn more about traffic rules here:

brainly.com/question/6034089

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4 0
2 years ago
Read 2 more answers
Find the current in 1 the electrical circuit below
Lesechka [4]

Answer:

  c.  25 μA

Explanation:

The dependent current source means that 31 times i1 will flow through the 6kΩ resistor, effectively increasing its voltage drop to 31 times that which would result from i1 alone. In effect, the 6kΩ resistor behaves in the left-side circuit loop as though it were 31×6kΩ = 186kΩ (with no dependent current source).

Then the current i1 is equivalent to that created by a 5+1 = 6V source through a 54kΩ +186kΩ = 240kΩ circuit impedance.

  (6V)/(240kΩ) = 25 μA

_____

<em>Additional comment</em>

The voltage across the 6kΩ resistor is (186/240)·6V = 4.65V, and the 25 μA current generates a voltage of 30·(25 μA)(1.8kΩ) = 1.35V across the 1.8kΩ resistor. This means the voltage source at the right side of the diagram needs to be at least 4.65 +1.35 = 6.0V in order to support the calculated voltage drops.

3 0
2 years ago
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