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HACTEHA [7]
3 years ago
6

A football player attempts a 30‐yd field goal. If he is able to impart a velocity u of 100 ft/sec to the ball, compute the minim

um angle θ. for which the ball will clear the crossbar of the goal. (Hint: Let m = tan θ)
Engineering
1 answer:
ki77a [65]3 years ago
4 0

Answer:2.53°

Explanation:The ball is undergoing a projectile motion that is why it has an angle

Range = (U^2 sin2a)/g

U= velocity of the ball=100ft/sec

Range of the ball(i.e horizontal distance the ball crossed)= 30yard=90ft

a=angle the ball is projected

g= acceleration due to gravity=9.8m/s^2

90=(100^2×sin2a)/9.8

90×9.8=10000×sin2a

882/10000=sin2a

0.0882=sin2a

Sin^-1 0.0882=2a

5.06=2a

a=5.06/2

a=2.53

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Answer:

(a) Increases

(b) Increases

(c) Increases

(d) Increases

(e) Decreases

Explanation:

The tensile modulus of a semi-crystalline polymer depends on the given factors as:

(a) Molecular Weight:

It increases with the increase in the molecular weight of the polymer.

(b) Degree of crystallinity:

Tensile strength of the semi-crystalline polymer increases with the increase in the degree of crystallinity of the polymer.

(c) Deformation by drawing:

The deformation by drawing in the polymer results in the finely oriented chain structure of the polymer with the greater inter chain secondary bonding structure resulting in the increase in the tensile strength of the polymer.

(d) Annealing of an undeformed material:

This also results in an increase in the tensile strength of the material.

(e) Annealing of  a drawn material:

A semi crystalline material which is drawn when annealed results in the decreased tensile strength of the material.

5 0
3 years ago
a torque of 24 ft pounds is the result when a force of ______ pounds is applied to a wrench that is 18 inches long.​
andrew-mc [135]

Answer:

  16

Explanation:

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  (1.5 ft)(x lbs) = 24 ft·lbs

  x lbs = (24 ft·lbs)/(1.5 ft) = 16 lbs

The force will be 16 pounds applied to an 18-inch wrench to obtain 24 ft·lbs.

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Answer:Its an electric train so there is no smoke so no where.

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