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Ostrovityanka [42]
3 years ago
7

Suppose the ice caps at the South and North poles melted due to the global warming and the water was distributed uniformly over

the earth's oceans. Would the earth angular velocity increase, decrease, or remain the same? Would each day get shorted or longer as compared to the current days? Explain.
Physics
1 answer:
Ray Of Light [21]3 years ago
5 0

Answer:

Explanation:

The Earth rotates about its axis once a day. Instead, the rate of rotation varies by up to a millisecond per day. The speed of the Earth’s rotation will increase if its mass is brought closer to its axis of rotation, that is net movement of mass. Conversely, the speed of the Earth’s rotation will decrease if its mass is moved away from the rotation axis.

Yes the days would be longer. Since the ice that was at the South Pole is now distributed around the world, there is a change in the distribution of mass.

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How did the astronomy of hipparchus and ptolemy violate the principles of early greek philosophers?
Mariana [72]

Answer: Hipparchus & Ptolemy believed sun and moon travel around circles with Earth in the middle (geocentric) while Plato and Aristotle believed Perfect unchanging heavens

Explanation: thus hipparchus and ptolemy violate early greek philosophy

8 0
3 years ago
One of the waste products of a nuclear reactor is plutonium-239 . This nucleus is radioactive and decays by splitting into a hel
Gekata [30.6K]

Answer:

a) v_{U-235} = 2.68 \cdot 10^{5} m/s

v_{He-4} = -1.57 \cdot 10^{7} m/s  

b) E_{He-4} = 8.23 \cdot 10^{-13} J

E_{U-235} = 1.41 \cdot 10^{-14} J

 

Explanation:

Searching the missed information we have:                                        

E: is the energy emitted in the plutonium decay = 8.40x10⁻¹³ J

m(⁴He): is the mass of the helium nucleus = 6.68x10⁻²⁷ kg  

m(²³⁵U): is the mass of the helium U-235 nucleus = 3.92x10⁻²⁵ kg            

a) We can find the velocities of the two nuclei by conservation of linear momentum and kinetic energy:

Linear momentum:

p_{i} = p_{f}

m_{Pu-239}v_{Pu-239} = m_{He-4}v_{He-4} + m_{U-235}v_{U-235}

Since the plutonium nucleus is originally at rest, v_{Pu-239} = 0:

0 = m_{He-4}v_{He-4} + m_{U-235}v_{U-235}  

v_{He-4} = -\frac{m_{U-235}v_{U-235}}{m_{He-4}}    (1)

Kinetic Energy:

E_{Pu-239} = \frac{1}{2}m_{He-4}v_{He-4}^{2} + \frac{1}{2}m_{U-235}v_{U-235}^{2}

2*8.40 \cdot 10^{-13} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2}    

1.68\cdot 10^{-12} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2}   (2)    

By entering equation (1) into (2) we have:

1.68\cdot 10^{-12} J = m_{He-4}(-\frac{m_{U-235}v_{U-235}}{m_{He-4}})^{2} + m_{U-235}v_{U-235}^{2}  

1.68\cdot 10^{-12} J = 6.68 \cdot 10^{-27} kg*(-\frac{3.92 \cdot 10^{-25} kg*v_{U-235}}{6.68 \cdot 10^{-27} kg})^{2} +3.92 \cdot 10^{-25} kg*v_{U-235}^{2}  

Solving the above equation for v_{U-235} we have:

v_{U-235} = 2.68 \cdot 10^{5} m/s

And by entering that value into equation (1):

v_{He-4} = -\frac{3.92 \cdot 10^{-25} kg*2.68 \cdot 10^{5} m/s}{6.68 \cdot 10^{-27} kg} = -1.57 \cdot 10^{7} m/s                        

The minus sign means that the helium-4 nucleus is moving in the opposite direction to the uranium-235 nucleus.

b) Now, the kinetic energy of each nucleus is:

For He-4:

E_{He-4} = \frac{1}{2}m_{He-4}v_{He-4}^{2} = \frac{1}{2} 6.68 \cdot 10^{-27} kg*(-1.57 \cdot 10^{7} m/s)^{2} = 8.23 \cdot 10^{-13} J

For U-235:

E_{U-235} = \frac{1}{2}m_{U-235}v_{U-235}^{2} = \frac{1}{2} 3.92 \cdot 10^{-25} kg*(2.68 \cdot 10^{5} m/s)^{2} = 1.41 \cdot 10^{-14} J

 

I hope it helps you!                                                                                    

3 0
3 years ago
A block with a weight of 9.0 N is at rest on a horizontal surface. A 1.2 N upward force is applied to the block by means of an a
lesya [120]

Answer:

a)   9 - 1.2 = 7.8 N

b) Since the force exerted by the box is it's weight, it acts in a downward direction. So the box will exert a force downward (perpendicular to the horizontal surface).

Explanation:

A 9N block would exert 9N of normal force on the horizontal plane under normal conditions. But in this case, we have a spring taking away some of the force by applying an upward force on the box.

So the force exerted by the box on the surface would now be:

a)   9 - 1.2 = 7.8 N

b) Since the force exerted by the box is it's weight, it acts in a downward direction. So the box will exert a force downward (perpendicular to the horizontal surface).

8 0
3 years ago
A bicycle has tires of radius 0.35 meters. If the bicycle is traveling at a constant speed of 7.8 m/s, at approximately what ang
lord [1]

22.3 rad/s

<h3>Further explanation</h3>

We will solve the question of uniform circular motion.

<u>Given:</u>

  • A bicycle has tires of radius \boxed{ \ R = 0.35 \ meters \ }
  • The bicycle is traveling at a constant speed of \boxed{ \ v = 7.8 \ m/s \ }

<u>Question:</u>

What angular speed are the tires rotating?

<u>The Process:</u>

Speed, angular speed, and radius are connected in the following formula:

\boxed{\boxed{ \ v = \omega R \ }}

The angular speed is worked out by

\boxed{ \ \omega = \frac{v}{R} \ }

All units are in the SI system so let us calculate the angular speed.

\boxed{ \ \omega = \frac{7.8 \ m/s}{0.35 \ m} \ }

Thus the value of the angular velocity of the rotating tire is \boxed{\boxed{ \ \omega = 22.3 \ rad/s \ }}

<u>An additional question:</u>

What is the frequency of tire rotation?

Recall this formula: \boxed{ \ \omega = 2 \pi f \ } \rightarrow \boxed{ \ f = \frac{\omega}{2 \pi} \ }

\boxed{ \ f = \frac{22.3 \ rad/s}{2 \pi} \ }

We get \boxed{\boxed{ \ f = 3.55 \ Hz \ }}

<h3>Learn more</h3>
  1. Arc CD is ²/₃ of the circumference of a circle. What is the radian measure of the central angle? brainly.com/question/2115496
  2. A triangle is rotated 90° about the origin brainly.com/question/2992432
  3. Particle's speed and direction of motion brainly.com/question/2814900

Keywords: a bicycle has tires of radius 0.35 meters. traveling, at a constant speed of 7.8 m/s, at approximately, angular speed, the tires rotating

7 0
3 years ago
What is the S.I Unit of electric flux?
Arada [10]

Answer:

Volt metre (Vm)

or Newton/Coulomb x (Metre)^2       (N/C x m^2)

8 0
3 years ago
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