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Ostrovityanka [42]
3 years ago
7

Suppose the ice caps at the South and North poles melted due to the global warming and the water was distributed uniformly over

the earth's oceans. Would the earth angular velocity increase, decrease, or remain the same? Would each day get shorted or longer as compared to the current days? Explain.
Physics
1 answer:
Ray Of Light [21]3 years ago
5 0

Answer:

Explanation:

The Earth rotates about its axis once a day. Instead, the rate of rotation varies by up to a millisecond per day. The speed of the Earth’s rotation will increase if its mass is brought closer to its axis of rotation, that is net movement of mass. Conversely, the speed of the Earth’s rotation will decrease if its mass is moved away from the rotation axis.

Yes the days would be longer. Since the ice that was at the South Pole is now distributed around the world, there is a change in the distribution of mass.

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Was the cannonball able to hit its target of 50 meters when the initial velocity was 20 m/s? Why?/Why Not?
frosja888 [35]

Answer:

The cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Explanation:

From the question given above, the following data were obtained:

Height to which the target is located = 50 m

Initial velocity (u) = 20 m/s

To know whether or not the cannon ball is able to hit the target, we shall determine the maximum height to which the cannon ball attained. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 20² – (2 × 10 × h)

0 = 400 – 20h

Collect like terms

0 – 400 = – 20h

– 400 = – 20h

Divide both side by – 20

h = – 400 / – 20

h = 20 m

Thus, the the maximum height to which the cannon ball attained is 20 m.

From the calculations made above, we can conclude that the cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

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In order for an object to move, the forces acting on it must be
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A5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.
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Explanation:

We have,

Height of object is 5 cm

Object distance from a convex lens is 18 cm

Focal length of convex lens is 10 cm

i.e. h = 5 cm

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f = +10 cm

Let v is distance of the image from the lens. Using lens formula :

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{(-18)}\\\\v=22.5\ cm

The magnification of lens is :

m=\dfrac{v}{u}=\dfrac{h'}{h}, h' is height of the image

\dfrac{v}{u}=\dfrac{h'}{h}\\\\h'=\dfrac{vh}{u}\\\\h'=\dfrac{22.5\times 4}{(-18)}\\\\h'=-5\ cm

h' = -5.00 cm (in three significant figures)

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Describe how positive and negatives pairs will react?
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A factor that determines the inertia of an object is
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the mass of the object determines the amount of inertia in an object
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