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kondaur [170]
3 years ago
13

Which topic are you most likely to find in a physics textbook?

Physics
2 answers:
iren2701 [21]3 years ago
6 0
You would find things like movement in a physics textbook
Darina [25.2K]3 years ago
5 0
I think the answer would be physics.
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Air bubbles being released when breathing from the mouth
Inessa [10]

Answer:

air embolism

Explanation:

8 0
2 years ago
Consider the free-body diagram. If you want the box to move, the force applied while dragging must be greater than the
VLD [36.1K]

You would want it to be greater than D. friction force

It needs be greater than the friction applied to it.

6 0
3 years ago
A Roller Derby Exhibition recently came to town. They packed the gym for two
arlik [135]

Answer:

14.36m/s

Explanation:

From the law of conservation of linear momentum

m1u1 + m2u2 = v(m1 + m2)

68×17 + 76×12= v(68+76)

1156+912 = 144v

2068 = 144v

v = 2068/144

=14.36 m/s

7 0
3 years ago
You yell into a canyon. You hear the echo in 3 seconds. How long did the sound of your voice travel before bouncing off a cliff?
Lilit [14]

Answer:

The sound travelled 516 meters before bouncing off a cliff.

Explanation:

The sound is an example of mechanical wave, which means that it needs a medium to propagate itself at constant speed. The time needed to hear the echo is equal to twice the height of the canyon divided by the velocity of sound. In addition, the speed of sound through the air at a temperature of 20 ºC is approximately 344 meters per second. Then, the height of the canyon can be derived from the following kinematic formula:

2\cdot h = v\cdot t (1)

Where:

h - Height, measured in meters.

v - Velocity of sound, measured in meters per second.

t - Time, measured in seconds.

If we know that  v = 344\,\frac{m}{s} and t = 3\,s, then the height of the canyon is:

h = \frac{v\cdot t}{2}

h = \frac{\left(344\,\frac{m}{s} \right)\cdot (3\,s)}{2}

h = 516\,m

The sound travelled 516 meters before bouncing off a cliff.

7 0
3 years ago
Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation dist
steposvetlana [31]

Answer:

The electric force between them is 878.9 N

Explanation:

Given:

Identical charge q = -6.25 \times 10^{-6}C

Separation between two charges r = 0.02 m

For finding the electrical force,

According to the coulomb's law

   F = \frac{k q^{2} }{r^{2} }

Here, force between two balloons are repulsive because both charges are same.

Where k = 9 \times 10^{9}

   F = \frac{9 \times 10^{9} \times (-6.25 \times 10^{-6} )^{2}  }{4 \times 10^{-4} }

   F = 878.9 N

Therefore, the electric force between them is 878.9 N

8 0
3 years ago
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