The results should be very similar if done correctly. There could always be room for error and they can differ. But if they differ too much, something is most likely wrong. :)
Answer:
81.08g of H
O will be produced.
Explanation:
Write down the balanced chemical equation:
⇒ 
⇒ 
Determine the limiting reagent:
:- 126/63.12646 = 1.995993 mol
1.995993/2 = 0.9979965
:- 192/31.9988 = 6.000225 mol
6.000225/12 = 0.50001875
Therefore,
, is the limiting reagent.
Use stoichiometry ratios to determine the number of moles of water produced:
: 
12 : 9
6.000225 : 4,500168756328362
Use the mole formula to calculate the mass of water produced:

SO4 -2, or Sulfate
Hope this helps! :)
Answer:
D. cathode; reduction
Explanation:
<em>Hope this helps~</em>
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