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4 years ago

Noooo links What is a biome?

Chemistry

2 answers:

Eva8 [605]4 years ago

6 0

The answer is B with the forest and stuff

cricket20 [7]4 years ago

5 0

Answer:

Explanation:

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One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that i

vagabundo [1.1K]

Answer:

The value is $U =1.3908 *10^{11} \ kg$

Explanation:

From the question we are told that

mass of carbon dioxide produced by one gallon of gasoline is $m = 9.50 \ kg$

The number of cars is $N = 40 \ million = 40 *10^{6} \ cars$

The distance covered by each car is $d = 7930 \ mi$

The rate is $R = 23.6 \ mi/ gallon$

Generally the amount of gasoline used by one car is mathematically represented as

$G = \frac{d}{R}$

=> $G = \frac{7930}{23.6}$

=> $G = 366 \ gallons$

Generally the amount of gasoline used by N cars is

$H = N * G$

=> $H = 40*10^{6} * 366$

=> $H = 1.464*10^{10} \ gallons$

Generally the annual production of carbon dioxide is mathematically represented as

$U = m * H$

=> $U =9.50 * 1.464*10^{10}$

=> $U =1.3908 *10^{11} \ kg$

8 0

4 years ago

Use the dichotomous key below to identify the cell type.

xenn [34]

The dichotomous key is not given here, however, the correct dichotomous key is as follows:

step- 1a cell has a nucleus and organelles - go to step 2

1b cell has no nucleus or organelles - bacterial cell

step- 2a cell has a cell wall - go to step 3

2b cell has no cell wall - animal cell

step- 3a cell has chloroplasts - plant cell

3b cell has no chloroplasts - fungal cell

Using this dichotomous key the cell can be identified as - Fungal cell.

A dichotomous key is an essential scientific tool that is used to find out the various kinds of organisms on their observable traits. Dichotomous keys have a series of statements with two different choices in each step that will take the student or user to the correct identification.

Identification of the given cell:

1. Follow step 1.

If cells have a nucleus and organelles - yes then go to step 2

2. follow step 2.

2a. if cell has a cell wall - yes go to step 3

3. follow step 3.

3a. if cell has chloroplasts - no then fungal cell

Fungal cells have a nucleus and cell organelles enclosed with a cell wall around the plasma membrane but do not have chloroplast.

Thus, Using this dichotomous key the cell can be identified as - Fungal cell.

Learn more about fungal cells:

brainly.com/question/14470940

6 0

3 years ago

25.0cm3 of s saturated potassium hydroxide is neutralized by 35.0cm3 of hydrogen chloride acid of concentration 0.75 mol/dm3. Ca

Kamila [148]

Answer:

Concentration of the original $\rm KOH$ solution: approximately $1.05\; \rm mol \cdot dm^{-3}$ .

Explanation:

Notice that the concentration of the $\rm HCl$ solution is in the unit $\rm mol\cdot dm^{-3}$ . However, the unit of the two volumes is $\rm cm^{3}$ . Convert the unit of the two volumes to $\rm dm^{3}$ to match the unit of concentration.

$\begin{aligned} V(\mathrm{NaOH}) &= 25.0\; \rm cm^{3} \\ &= 25.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0250\; \rm dm^{3} \end{aligned}$ .

$\begin{aligned} V(\mathrm{HCl}) &= 35.0\; \rm cm^{3} \\ &= 35.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0350\; \rm dm^{3} \end{aligned}$ .

Calculate the number of moles of $\rm HCl$ molecules in that $0.0350\; \rm dm^{3}$ of $0.75\; \rm mol \cdot dm^{3}$ $\rm HCl\!$ solution:

$\begin{aligned}n(\mathrm{HCl}) &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.00350\; \rm dm^{3} \times 0.75\; \rm mol \cdot dm^{3} \\ &\approx 0.02625\; \rm mol\end{aligned}$ .

$\rm HCl$ is a monoprotic acid. In other words, each $\rm HCl\!$ would release up to one proton $\rm H^{+}$ .

On the other hand, $\rm KOH$ is a monoprotic base. Each $\rm KOH\!$ formula unit would react with up to one $\rm H^{+}$ .

Hence, $\rm HCl$ molecules and $\rm KOH\!$ formula units would react at a one-to-one ratio.

${\rm HCl}\, (aq) + {\rm NaOH}\, (aq) \to {\rm NaCl}\, (aq) + {\rm H_2O}\, (l)$ .

Therefore, that $0.02625\; \rm mol$ of $\rm HCl$ molecules would neutralize exactly the same number of $\rm NaOH$ formula units. That is: $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ .

Calculate the concentration of a $\rm NaOH$ solution where $V(\mathrm{NaOH}) = 0.0250\; \rm dm^{3}$ and $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ :

$\begin{aligned}c(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{V(\mathrm{NaOH})} \\ &= \frac{0.02625\; \rm mol}{0.0250\; \rm dm^{3}}\approx 1.05\; \rm mol \cdot dm^{-3}\end{aligned}$ .

7 0

3 years ago

How many joules are required for melting 12.8g of ice at 0 degrees Celsius?

tino4ka555 [31]

Answer:

4,270 Joules

Explanation:

The heat of fusion of water is 334 j/g. So, the equation would be (12.8 g)(334 j/g) which comes to 4,270 joules.

Written out that's just twelve point eight times three hundred and thirty four.

4 0

3 years ago

Hello can you please help me to solve above questions. .

topjm [15]

Answer:

i)a. P & R

b. Q& S

ii) R

iii) Atomic no & Atomic radius

2)a. C4H10

b. CH3Cl

7 0

3 years ago