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3 years ago

Physical system

Physics

2 answers:

ch4aika [34]3 years ago

8 0

Answer:

this happens because there is gravitational force acting upon it.

Reptile [31]3 years ago

7 0

Answer:

The book will fall when you drop it and make a thud, It falls on the floor because there is no force holding it up, but there is a force pulling it down, the gravitational force. It doesnt rise higher in the air because It does have lighter like the properties of a balloon.

Explanation:

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A 2kg mass is moving at 3m/s. What is its kinetic energy?

Romashka [77]

Explanation:

$\frac{1}{2}m {v}^{2} \\ \frac{1}{2} \times 2 \times {3}^{2} \\ 1 \times 9 = 9j$

8 0

2 years ago

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Two strong permanent magnets are placed one inch apart. Which two fundamental forces will most affect them?

Anuta_ua [19.1K]

The answer i got was c. gravity and strong
i hope it helps

3 0

3 years ago

An electron is released from rest at a distance of 0.570 m from a large insulating sheet of charge that has uniform surface char

Lelu [443]

Explanation:

Formula to calculate the electric field of the sheet is as follows.

E = $\frac{\sigma}{2 \epsilon_{o}}$

And, expression for magnitude of force exerted on the electron is as follows.

F = Eq

So, work done by the force on electron is as follows.

W = Fs

where, s = distance of electron from its initial position

= (0.570 - 0.06) m

= 0.51 m

First, we will calculate the electric field as follows.

E = $\frac{\sigma}{2 \epsilon_{o}}$

= $\frac{4.60 \times 10^{-12}C/m^{2}}{2 \times 8.854 \times 10^{-12}C^{2}/N m^{2}}$

= 0.259 N/C

Now, force will be calculated as follows.

F = Eq

= $0.259 N/C \times 1.6 \times 10^{-19} C$

= $0.415 \times 10^{-19} N$

Now, work done will be as follows.

W = Fs

= $0.415 \times 10^{-19} N \times 0.51 m$

= $2.12 \times 10^{-20} J$

Thus, we can conclude that work done on the electron by the electric field of the sheet is $2.12 \times 10^{-20} J$ .

3 0

4 years ago

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Given that the concentration of bovine carbonic anhydrase is 3.3 pmol ⋅ L − 1 and R max ( V max ) = 222 μmol ⋅ L − 1 ⋅ s − 1 , d

LuckyWell [14K]

Answer:

The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.

Explanation:

Given:

The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1

The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1

The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1

Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1

3 0

4 years ago

How to find net horizontal force with friction and applied force?

wlad13 [49]

Just subtract the both of them.

7 0

4 years ago