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3 years ago

14

Physical system

2 answers:

ch4aika [34]3 years ago

8 0

Answer:

this happens because there is gravitational force acting upon it.

Reptile [31]3 years ago

7 0

Answer:

The book will fall when you drop it and make a thud, It falls on the floor because there is no force holding it up, but there is a force pulling it down, the gravitational force. It doesnt rise higher in the air because It does have lighter like the properties of a balloon.

Explanation:

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180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?

ale4655 [162]

Explanation:

Work done= MGH

180=m×10×3

180/30=m

m=6kg

4 0

3 years ago

How much faster does sound travel in the ocean been in the rain forest?show your work.

Natasha2012 [34]

In rainforest sound travels faster because in the ocean sound travels very slow due to the pressure

5 0

3 years ago

A 87 kg man has a total mechanical energy of 1780 J .If he is swinging downward and is currently 1.4 m above the ground, what is

borishaifa [10]

Answer:

6.4m/s

Explanation:

The total mechanical energy of the man is 1780J.

This mechanical energy is the energy due to the motion of the body and it is a form of kinetic energy.

Also, mass = 87kg

Kinetic energy = $\frac{1}{2}$ m v²

m is the mass

v is the velocity

1780 = $\frac{1}{2}$ x 87 x v²

v² = 40.9

v = 6.4m/s

4 0

3 years ago

kap26 [50]

<h2>A is the correct answer!</h2><h3></h3><h3>I'm too lazy to explain :(</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>

6 0

3 years ago

An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s . Suppose that

RUDIKE [14]

Answer:

0.0241875 m

Explanation:

$m_1$ = Mass of quarterback = 80 kg

$m_2$ = Mass of football = 0.43 kg

$v_1$ = Velocity of quarterback

$v_2$ = Velocity of football = 15 m/s

Time taken = 0.3 seconds

In this system as the linear momentum is conserved

$m_1v_1+m_2v_2=0\\\Rightarrow v_1=-\frac{m_2v_2}{m_1}\\\Rightarrow v_1=-\frac{0.43\times 15}{80}\\\Rightarrow v_1=0.080625\ m/s$

Assuming this velocity is constant

$Distance=Velocity\times Time\\\Rightarrow Distance=0.080625\times 0.3\\\Rightarrow Distance=0.0241875\ m$

The distance the quarterback will move in the horizontal direction is 0.0241875 m

4 0

3 years ago