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Leya [2.2K]
3 years ago
11

Is god real??? i wanna know

Physics
2 answers:
ivann1987 [24]3 years ago
7 0
Yes He is real!!! He has proved it in my own life as well as the lives of others. I highly encourage believing in Him!!!
NemiM [27]3 years ago
6 0
In my opinion, yes the bible tell us that "For God so loved<span> the world that he gave</span><span> his one and only Son,</span><span> that whoever believes</span><span> in him shall not perish but have eternal life" 
So my answer is yes</span>
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Reciprocal liking is adaptive because it lowers the risk of relationship rejection.
Mila [183]
I believe that the statement above is TRUE. I can say that it's true because based on the definition of what reciprocal liking is, this is the probability of having to like someone who also likes them in return. Therefore, if they like each other, this means that there is a low risk of rejection in the relationship.
6 0
3 years ago
Read 2 more answers
A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve
Troyanec [42]

The velocity of tennis racket after collision is 14.96m/s

<u>Explanation:</u>

Given-

Mass, m = 0.311kg

u1 = 30.3m/s

m2 = 0.057kg

u2 = 19.2m/s

Since m2 is moving in opposite direction, u2 = -19.2m/s

Velocity of m1 after collision  = ?

Let the velocity of m1 after collision be v

After collision the momentum is conserved.

Therefore,

m1u1 - m2u2 = m1v1 + m2v2

v1 = (\frac{m1-m2}{m1+m2})u1 + (\frac{2m2}{m1+m2})u2

v1 = (\frac{0.311-0.057}{0.311+0.057})30.3 + (\frac{2 X 0.057}{0.311 + 0.057}) X-19.2\\\\v1 = (\frac{0.254}{0.368} )30.3 + (\frac{0.114}{0.368}) X -19.2\\ \\v1 = 20.91 - 5.95\\\\v1 = 14.96

Therefore, the velocity of tennis racket after collision is 14.96m/s

7 0
3 years ago
1. Is the relationship between velocity and centripetal force a direct, linear relationship or is it a nonlinear square relation
Svetllana [295]

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

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3 years ago
Which statement best describes the relationship between atoms and nuclear forces? (2 points)
Setler79 [48]

Answer:

D. Strong nuclear forces hold the nucleus of an atom together. Weak nuclear forces are involved when certain types of atoms break down.

Explanation:

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2 years ago
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