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Tasya [4]
2 years ago
8

Consider a spherical capacitor with radius of the inner conducting sphere a and the outer shell b. The outer shell is grounded (

i.e., it is at zero potential). The charges are +Q and −Q. a A B +Q −Q b What is the magnitude of electric field at in the region between the sphere and the outer

Physics
1 answer:
AleksAgata [21]2 years ago
6 0

Answer:

Explanation:

The application of Gauss's law is used in the derivation as shown with detailed step by step in the attached file.

The potential difference on this spherical capacitor is ΔV = Va - Vb = kQ/a - kQ/b = kQ(1/a - 1/b)

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The charge on a charged sphere is concentrated on its <u>center</u> .

<u>Explanation : </u>

The charge on a charged sphere is just concentrated in the center of a shell. We can also say that that the charges are being distributed across the charged sphere. This is totally because of the absence of the electric field. In other words, we can say that, inside a conductor, the electric field is zero.

And that is why the charges are distributed across the surface. Due to the electrostatic forces inside the nucleus or the atom, the apparent forces get cancelled and thus the electric field becomes zero.    

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Answer:

Δd = 7.22 10⁻² m

Explanation:

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how the angles are small

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we substitute  

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let's use direct ruler rule to find the distance between two slits

           

If there are 500 lines in 1 me, what distance is there between two lines

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diffraction gratings are built so that most of the energy is in the first order of diffraction m = 1

let's calculate for each wavelength

λ = 656 nm = 656 10⁻⁹ m

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         d₁ = 2.788 10⁻¹ m

λ = 486 nm = 486 10⁻⁹ m

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         d₂ = 2.066 10⁻¹ m

the distance between the two lines is

         Δd = d1 -d2

         Δd = (2,788 - 2,066) 10⁻¹

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Answer:

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It should be noted that this explosion can be annoying to the human ear.

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