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maw [93]
3 years ago
12

What’s a good science fair idea that includes lollies?

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
8 0
Like lollipops?........
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Calculate the acceleration of a car if its speed increases from 4.0 m/s to 16 m/s in 3.7 s.
ioda

Answer:

3.24m/s^2

Explanation:

The following data were obtained from the question:

U = 4m/s

V = 16m/s

t = 3.7secs

Acceleration is change in velocity with time i.e

a = (V — U) / t

a = (16 — 4) / 3.7

a = 12/3.7

a = 3.24m/s^2

8 0
3 years ago
The early ancestors of the horse (shown in the picture) were adapted to life in tropical forests. Gradually the forests disappea
Gre4nikov [31]

So here you go are taller with long legs and are capable of great speed to escape predators

8 0
3 years ago
Read 2 more answers
Of the elements calcium, Ca, beryllium, Be, barium, Ba, and strontium, Sr, which has the largest atomic radius? Explain your ans
Nezavi [6.7K]
The largest atomic radius has Ba,because they are all metals of 2nd group,but as you know when you go down upright in the periodic table the metallic features getting stronger but also orbital layers increasing,and you can say more layers larger atomic radius.Hope I helped,sorry for English
8 0
3 years ago
Read 2 more answers
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
Assoli18 [71]

Answer:

The specific heat of copper is 0.385 J/g°C

Explanation:

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 425 mL of water at 22.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?

Step 1: Data given

Mass of copper = 85.2 grams

Temperature of copper = 221.32 °C

Volume of water = 425 mL

Temperature of water = 22.55 °C

Final temperature = 26.15 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculat the specific heat of copper

Heat lost = heat gained

Q = m*c*ΔT

Qcopper = -Qwater

m(copper)*c(copper)*ΔT(copper) = - m(water) * c(water) * ΔT(water)

⇒ m(copper) = 85.2 grams

⇒ c(copper) = TO BE DETERMINED

⇒ ΔT(copper) = the change in temeprature = T2 -T1 = 26.15 -221.32 = -195.17 °C

⇒ m(water) = The mass of water = 425 mL * 1g/mL = 425 grams

⇒ c(water) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = 26.15 - 22.55 = 3.6

85.2 * c(copper) * (-195.17) = -425 * 4.184 * 3.6

c(copper) = 0.385 J/g°C

The specific heat of copper is 0.385 J/g°C

(Note, The original question says the volume of the water is 4250 mL. IF this is not an error, the specific heat of copper is 3.85 J/g°C (10x higher than the normal value).

8 0
3 years ago
When the molecules in a body move with increased speed, it's possible that the body will change from a
Norma-Jean [14]
The answer is B
liquid to a gas

8 0
4 years ago
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