Which molecule is amphoteric? A) NH4+ B )H2O C )H2CO3− D )H2SO4

Chemistry

2 answers:

fiasKO [112]3 years ago

5 0

Answer: B ) $H_2O]$

Explanation:- According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

Amphoteric substances are substances which can act as both acids and bases and thus can accept and donate $H^+$ ions.

$H_2O\rightarrow H^++OH^_$

Here water acts as an acid as it donates $H^+$ ions.

$H_2O+H^+\rightarrow H_3O^+$

Here water acts as a base as it accepts $H^+$ ions.

Maslowich3 years ago

4 0

The answer is letter choice B

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Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.90 moles of magnesium perchlorate, Mg(ClO4)2.

Lady bird [3.3K]

Answer:

5.90, 11.8, 47.2

Explanation:

Let’s remove the parentheses and write the formula as MgCl₂O₈.

We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.

∴ $\text{Moles of Mg atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{1 mol Mg atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{5.90 mol Mg atoms}$

$\text{Moles of Cl atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{2 mol Cl atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{11.8 mol Cl atoms}$

$\text{Moles of O atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{8 mol O atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{47.2 mol O atoms}$