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kupik [55]
3 years ago
6

Complete the equation for the reaction of sulfuric acid and sugar (sucrose). C12H22O11 + 11 H2SO4 ? 12 + 11 H2SO4 + 11

Chemistry
1 answer:
serg [7]3 years ago
7 0

Answer :

The complete equation for the reaction of sulfuric acid and sugar is,

C_{12}H_{22}O_{11}+11 H_2SO_4\rightarrow 12C+11H_2SO_4+11H_2O

By the stoichiometry of the reaction,

1 mole of sucrose react with the 11 moles of sulfuric acid to give 12 moles of carbon and 11 moles of water.

In this reaction, sulfuric acid react with sucrose (sugar). It dehydrates the sugar molecules which means it eliminates the water.

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5.00 L of air at 750 mmHg pressure was compressed into a 3.00 L steel cylinder. What is the final pressure? (round to significan
kozerog [31]

Answer:

P2 = 1250mmHg

Explanation:

V1 = 5.0L

P1 = 750mmHg

V2 = 3.0L

P2 = ?

According to Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

P = k/V k = P*V

P1*V1 = P2*V2 = P3*V3 =........=Pn*Vn

P1 *V1 = P2 * V2

Solve for P2

P2 = (P1 * V1) / V2

P2 = (750 * 5.0) / 3.0

P2 = 3750 / 3

P2 = 1250mmHg

The final pressure of the gas is 1250mmHg

5 0
3 years ago
Which one of the following polymer is prepared by condensation polymerization?
nikitadnepr [17]

The answer is Darcon my friend, have a fantastic day

8 0
3 years ago
Read 2 more answers
Help on part "c": The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0g of luminol
Contact [7]

1. The molarity of the stock solution of luminol = 1,431 M

2. 0.12 moles of luminol is present in 2.00 L of the diluted spray

3. The volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B): 83.86 ml

<h3>Further explanation</h3>

Stoichiometry in Chemistry studies about chemical reactions mainly emphasizing quantitative, such as the calculation of volume, mass, amount, which is related to the number of ions, molecules, elements, etc.

In stoichiometry included :

  • 1. Relative atomic mass
  • 2. Relative molecular mass

is the relative atomic mass of the molecule

  • 3. mole

1 mole is the number of particles contained in a substance with the same number of atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) by the relative mass of the element or the relative mass of the molecule

\large{\boxed{\bold{mol\:=\:\frac{grams}{ relative\:mass} }}}

Luminol (C₈H₇N₃O₂) is a substance used to detect traces of blood in the scene of a crime because it reacts with iron in the blood

a. a luminol stock solution by adding 19.0g of luminol into a total volume of 75.0mL of H2O.

So the molarity is

  • 1. Luminol mole

- the relative molecular mass of Luminol

= 8. C + 7.H + 3.N + 2.16

= 8.12 + 7.1 + 3.14 + 2.16

= 177 grams / mol

so the mole:

mol = gram / relative molecular mass

mole=\frac{19}{177}

mole = 0.1073

2. Molarity (M)

M = mole / volume

M\:=\:{\frac{ 0.1703 }{75.10^{-3} L}

M = 1,431

  • b. luminol concentration in a spray bottle 6.00 × 10⁻² M. So that in 2 L of solution, the number of moles is:

mole = M x volume

mole = 6.10⁻² x 2

mole = 0.12

  • c. Molarity of the stock solution (Part A) = 1,431 M

the number of moles present in the diluted solution (Part B) = 0.12

So the volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B) is:

volume = mol / M

volume\:=\:\frac{0.12}{1.431}

volume = 0.08386 L = 83.86 ml

<h3>Learn more</h3>

moles of water you can produce

brainly.com/question/1405182

the number of each atom present in the compound's formula

brainly.com/question/5303004

the ratio of hydrogen atoms (H) to oxygen atoms (O) in 2 l of water

brainly.com/question/10861183

Keywords: mole, volume, molarity, Luminol, the relative molecular mass

6 0
3 years ago
Read 2 more answers
Write a balanced chemical equation, including physical state symbols, for the combustion of gaseous butane into gaseous carbon d
Phantasy [73]

Answer:1.

1.Balanced equation

C4H10 + 9 02 ==> 5H20 +4CO2

2. Volume of CO2 =596L

Explanation:

1.Combustion of alkane is the reaction of alkanes with Oxygen. And the general equation for the combustion is;

CxHy +( x+y/4) O2 ==> y/2 02 + xCO2

Where x and y are number of carbon and hydrogen atoms respectively.

For butane (C4H10)

x=4 and y=10

Therefore

C4H10 + 9 02 ==> 5H20 +4CO2

2. Mass of butane = 0.360kg

Molar mass of C4H10 = ( 12×4 + 1×10)

= 48 +10=58g/mol= 0.058kg/mol

Mole = mass/molar mass

Mole = 0.360/0.058= 6.2moles

From the stoichiometric equation

1mole of C4H10 will gives 4moles of CO2

Therefore

6.2moles of C4H10 will gives 4 moles of 24.8 moles of CO2

Using the ideal gas equation

PV=nRT

P= 1.0atm

V=?

n= 24.8mol.

R=0.08206atmL/molK

T=20+273=293

V= 24.8 × 0.08206 × 293

V= 596L

Therefore the volume of CO2 produced is 596L

8 0
3 years ago
How many molecules are there in the following 25.0 g H2SO4
NeX [460]

Answer:

1.536×10^23

Explanation:

One mole of any compound has N molecules.

Where N is the Avogadro's number

Molecular weight of H2SO4 is

H2 = 2

SO4 = 96

H2SO4 = 2+96

98g/mol

Hence the number of mole of H2SO4 in 25g = 25/98 = 0.2551mol

Number of molecules = 25/98 × 6.022×10^23

= 1.536×10^23 molecules

7 0
3 years ago
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