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marissa [1.9K]
3 years ago
11

How many electrons have been removed from a positively charged electroscope if it has a net charge of 6x10-11?

Physics
1 answer:
oksano4ka [1.4K]3 years ago
5 0

Answer:

is it the ans you are looking for

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Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.20×10^6 N, one at an angle 14.0∘ west of north,
laila [671]

Answer:

1.45544 J

Explanation:

See attachment

5 0
3 years ago
Which is the best example of the concept of heredity? A. A black cat blends into its environment at night. B. A baby has his mot
Hitman42 [59]
B) A baby has his mother's hair and eye color 
4 0
3 years ago
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What is the relationship between an object’s mass and its gravitational potential energy?.
antiseptic1488 [7]

Answer:

If we’re talking about objects on the Earth, the gravitational potential energy is given by:

Explanation:

PEg=mgh

so the energy is proportional to the mass ( m ), but also to the strength of the gravitational field ( g ), and the height ( h ) to which the mass is lifted.

5 0
2 years ago
A phoneme is the largest unit of sound in a word.
lukranit [14]

This question is incomplete; here is the complete question:

A phoneme is the largest unit of sound in a word. Please select the best answer from the choices provided

A. T

B. F

The correct answer to this question is F (False)

Explanation:

The word "phoneme" is used to refer to the minimal unit of sound in words, and therefore in language. For example, the first phoneme in the word "man" is "m". These units of sound are essential in language because they make each word unique in meaning and sound. For example, "fan" and "man" are different due to the phonemes "m" and "f". According to this, the phone is not the largest unit of sound but the smallest unit.

7 0
3 years ago
Read 2 more answers
flipper (the dolphin) is out in the open ocean hunting tuna avec. he emits his pulse at 22khz and .42 seconds later he hears it
marusya05 [52]
First we need to find the speed of the dolphin sound wave in the water. We can use the following relationship between frequency and wavelength of a wave:
v=\lambda f
where
v is the wave speed
\lambda its wavelength
f its frequency
Using \lambda = 2 cm = 0.02 m and f=22 kHz = 22000 Hz, we get
v=(0.02 m)(22000 Hz)=440 m/s

We know that the dolphin sound wave takes t=0.42 s to travel to the tuna and back to the dolphin. If we call L the distance between the tuna and the dolphin, the sound wave covers a distance of S=2 L in a time t=0.42 s, so we can write the basic relationship between space, time and velocity for a uniform motion as:
v= \frac{S}{t}= \frac{2L}{t}
and since we know both v and t, we can find the distance L between the dolphin and the tuna:
L= \frac{vt}{2}= \frac{(440 m/s)(0.42 s)}{2}=92.4 m
5 0
3 years ago
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