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ASHA 777 [7]
3 years ago
12

se the following key to classify each of the elements below in its elemental form: A. Discrete atoms ... C. Metallic lattice B.

Molecules ... D. Extended, three-dimensional network 1. Calcium 2. Helium ... 3. Sulfur 4. Potassium ...
Chemistry
1 answer:
Lostsunrise [7]3 years ago
4 0

Explanation:

the correct match can as follows:

1.  helium ⇒ discrete atoms (helium is an inert gas)

2. oxygen ⇒ molecules (oxygen exists in molecular form as O2)

3 Magnesium ⇒ matalic lattice ( Magnesium is a metal FCC crystal Structure :) )

4 Aluminum⇒ covalent network (since it is situated in the middle of the group and posses amphoteric properties too)

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If 100% is not passed from one trophic level to the next, where does this energy go?
Sonja [21]
D is the answer to question

6 0
2 years ago
Read 2 more answers
A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

Best regards!

8 0
2 years ago
A gas has a volume of 30 L at 105 kPa. What pressure is required to compress the gas to 21 L?
Aloiza [94]

Answer: 150 kPa

Explanation:

Given that,

Original volume of gas V1 = 30L

Original pressure of gas P1 = 105 kPa

New pressure of gas P2 = ?

New volume of gas V2 = 21L

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

105 kPa x 30L = P2 x 21L

3150 kPa L = P2 x 21L

P2 = 3150 kPa L / 21 L

P2 = 150 kPa

Thus, 150 kPa of pressure is required to compress the gas

8 0
3 years ago
3. Nitrogen, when combined with oxygen, can form various oxides. 3.5 g of nitrogen gas is burned in oxygen to form 11.5 g of an
Pavel [41]

Answer:

A.

Explanation:

5 0
3 years ago
What is the reaction of lead with sulphuric acid
vesna_86 [32]
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<span>lead + sulphuric acid —> lead sulphate + hydrogen
Pb(s) + H2SO4 (aq) —> PbSO4(aq) + H2(g)</span> 

<span>Lead reacts very slowly with dilute nitric acid to give </span>lead nitrate<span> and </span>hydrogen<span> gas. </span>

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7 0
3 years ago
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