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Contact [7]
3 years ago
8

A baseball diamond is a square (don’t be fooled that it is usually shown rotated by 45°). Each side of the square is 90 feet lon

g (to two significant figures). How far must a fielder throw the ball from second base to home plate?
Physics
1 answer:
gayaneshka [121]3 years ago
8 0

A line from second to home creates a right triangle with 45 degree angles.

This makes the diagonal line the side length of the square multiplied by the sqrt(2)

Second to home = 90sqrt(2) = 127.279 feet ( round answer as needed)

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Answer:

\mu_k=0.101

Explanation:

It is given that,

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Compression in the spring, x = 5 m

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\dfrac{1}{2}kx^2=\mu_k mgh

\mu_k=\dfrac{kx^2}{2mgh}

\mu_k=\dfrac{95\times (5)^2}{2\times 60\times 9.8\times 19.8}

\mu_k=0.101

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