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erik [133]
4 years ago
9

While riding in a hot air balloon, which is steadily descending at a speed of 1.01 m/s, you accidentally drop your cell phone?

Physics
1 answer:
mote1985 [20]4 years ago
5 0

While riding in a hot air balloon, which is steadily at a speed of 1.01 m/s, and your phone accidentally falls.

<span>(a)    </span>The speed of your phone after 4 s is:

V= u + at

V= 1.01 + (9.8)(4)

V= 40.21 m/s

<span>(b)   </span>The balloon is ____ far:

V = u + at

V= 1.01 + (9.8)(1)

V=10.81 –distance at 1 one second

V= u + at

V= 1.01 + (9.8)(2)

V= 20.61-distance at 2 seconds

V= u+ at

V= 30.41- distance at 3 seconds

V= 40.21- distance at 4 seconds

D= 102.04 m

<span>(c)    </span>If the balloon is rising steadily at 1.01 m/s:

V= -1.1 m/s

<span> </span>

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Answer:

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olga55 [171]

Explanation:

It is given that,

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Current, I = 0.2 A

(1.) Approximate formula:

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Please help me with my science homework
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