Answer:
voltage= 17.88volts
current= 0.04 amps
Explanation:
Step one:
given data
resistance R=400 ohms
Power P= 0.8W
a. What is the maximum voltage that can be applied across this resistor without damaging it?
the expression relating power and voltage is
P=V^2/R
substituting we have
0.8=V^2/400
V^2=0.8*400
V^2=320
V=√320
V=17.88 volts
the maximum voltage is 17.88volts
b.What is the maximum current it can draw?
we know that from Ohm' law
V=IR
17.88=I*400
I=17.88/400
I=0.04amps
Answer:
I am not really sure but i think its option 2
Explanation:
Answer:When the battery is connected to a circuit, electrons produced by the chemical reaction at the anode flow through the circuit to the cathode. ... Batteries put out direct current, as opposed to alternating current, which is what comes out of a wall socket. With direct current, the charge flows only in one direction.
Explanation:
Answer:
C
Explanation:
The sun has rotated causing the shadow to reflect.
Answer:
96 m
Explanation:
Given:
v₀ = 0 m/s
a = 3 m/s²
t = 8 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (8 s) + ½ (3 m/s²) (8 s)²
Δx = 96 m
