Question

If we measure the temperature of a blackbody to be about 300 K (a typical air temperature in Florida), at what wavelength would this blackbody's intensity have its maximum, and where in the electromagnetic spectrum is this wavelength?

Answer 1

Answer:

9.66 x 10^-6 m

Explanation:

Use the Wein's displacement law

$\lambda _{m}\times T = b$

Where, b is the Wein's constant

b =  2.898 x 10^-3 meter-kelvin

So, λm x 300 =  2.898 x 10^-3

λm = 9.66 x 10^-6 m