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anyanavicka [17]

2 years ago

6

Suppose a piece of dust has fallen on a CD. If the spin rate of the CD is 500 rpm, and the piece of dust is 4.3 cm from the cent

er, what is the total distance traveled by the dust in 3 minutes? (Ignore accelerations due to getting the CD rotating.)

1 answer:

Lynna [10]2 years ago

5 0

Answer:

s = 405.27 m

Explanation:

given,

spin rate of the CD = 500 rpm

distance of dust, r = 4.3 cm

time = 3 minute = 3 x 60 = 180 s

total distance traveled by the dust, d = ?

$\omega = 500\times \dfrac{2\pi}{60}$

$\omega = 52.36\ rad/s$

we know,

$\Delta \theta = \omega\ t$

$\Delta \theta =52.36\times 180$

$\Delta \theta = 9424.8\ rad$

distance traveled by the dust particle

s = Δ θ x r

s = 9424.8 x 0.043

s = 405.27 m

Hence, distance traveled by the dust particle is 405.27 m

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