Suppose a piece of dust has fallen on a CD. If the spin rate of the CD is 500 rpm, and the piece of dust is 4.3 cm from the cent
1 answer:
Answer:
s = 405.27 m
Explanation:
given,
spin rate of the CD = 500 rpm
distance of dust, r = 4.3 cm
time = 3 minute = 3 x 60 = 180 s
total distance traveled by the dust, d = ?
we know,
distance traveled by the dust particle
s = Δ θ x r
s = 9424.8 x 0.043
s = 405.27 m
Hence, distance traveled by the dust particle is 405.27 m
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Answer:
The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.
at r < R:
Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.
E = 0.
at R < r < 2R:
The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.
at 2R < r:
The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.
Explanation:
Gauss’ Law is straightforward when applied to spheres. The area of the sphere is , and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.
