Answer:
i need the describtion like what i need to do
Explanation:
Answer:
a. the product of the current and the time interval
Explanation:
the basic formula is: 
current means the time rate of flow of charge: 
where Q - charge
I - current
t - time
Answer:
6.23×10^(14) particles
Explanation:
Let the total power be P_0
now according to question
5% ×P_0=30W
so P_0=30/0,05=600 W.
an alpha particle'energy is 5.5 MeV
Let n be number of alpha particles emitted per sec.
Therefore,
n=600J/5.5MeV=600/(5.5×e^6×1.6×e^-19)=6.82×e^14(particles)
Answer:
force at the top will be 388 N which is nearly equal to 389
option (b) is correct
Explanation:
We have given velocity of the moving car v = 10 m/sec
Radius of the circular section r = 30 m
Mass of the passenger m = 60 kg
Acceleration due to gravity 
At the top normal force is given by 
So force at top will be 
So force at the top will be 388 N which is nearly equal to 389
So option (b) is correct
Answer:
The time it will take for the driver to reach Ottawa is 3 hours 32 minutes and 45 seconds
Explanation:
The given parameters are;
Speed of the car = 120 km/h
Distance from Toronto to Ottawa = 425.5 km
The formula for speed is given as follows;
Speed = Distance/Time
Therefore, to find the time duration it takes from Toronto to Ottawa, we have;
Time duration = Distance from Toronto to Ottawa/(Speed of the car)
The time duration = 425.5/120 = 3.54583 hours = 212.75 min = 12765 seconds
The time it takes from Toronto to Ottawa while driving at 425.5 km/h = 12765 seconds.
