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3 years ago

If the earth rock takes 2.00 s to reach its highest point, how long will it take the moon rock to do so

Physics

1 answer:

spin [16.1K]3 years ago

8 0

12.0 s

Explanation:

First, let's find the initial vertical velocity of the rock on earth. We know that

vy = v0y - gt

where g = 9.8 m/s^2. When the rock reaches its highest point, vy = 0. So if it takes 2.00 s to reach the maximum height, the initial velocity of the rock is

v0y = (9.8 m/s^2)(2.00 s) = 19.6 m/s.

We know that the moon only has 1/6 of earth's gravity. Therefore, if the same rock is given the same vertical velocity as on earth, then the time it takes to reach its maximum height is

voy = gt ---> t = voy/g

t = (19.6 m/s)/(9.8/6 m/s^2)

= 12.0 s

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The atmospheric pressure on the top of the Engineering Sciences Building (ESB) is 97.6 kPa, while that in Room G39-ESB (ground f

Stells [14]

Answer:

Δ h = 52.78 m

Explanation:

given,

Atmospheric pressure at the top of building = 97.6 kPa

Atmospheric pressure at the bottom of building = 98.2 kPa

Density of air = 1.16 kg/m³

acceleration due to gravity, g = 9.8 m/s²

height of the building = ?

We know,

Δ P = ρ g Δ h

(98.2-97.6) x 10³ = 1.16 x 9.8 x Δ h

11.368 Δ h = 600

Δ h = 52.78 m

Hence, the height of the building is equal to 52.78 m.

6 0

3 years ago

What happens to the bulb when the battery changes from 1.5V to 9v?

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Answer:

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4 0

3 years ago

If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does it have?

aksik [14]

Answer: 2200J

Explanation:

M = 44kg

V = 10m/s

K.E =?

K.E = 1/2MV2 = 1/2 x 44 x (10)^2

K.E = 22 x 100

K.E = 2200J

8 0

4 years ago

True or False:

bekas [8.4K]

I think it false. Sorry if i'm wrong.

5 0

3 years ago

Read 2 more answers

The atmosphere of Mars is almost all carbon dioxide and the average surface pressure is 610 Pa (as compared with 101,000 Pa on E

Karolina [17]

Answer:

z = 3,737 10⁵ m

Explanation:

a) As they indicate that the atmosphere behaves like an ideal gas, we can use the equation

P V = n R T

P = (n r / V) T

We replace

P = (n R / V) T₀ $e^{- C z}$

b) Let's apply this equation in the points

Lower

.z = 0

P₀ = 610 Pa

P₀ = (nR / V) T₀

Higher.

P = 10 Pa

P = (n R / V) T₀ e^{- C z}

We replace

P = P₀ e^{- C z}

e^{- C z} = P / P₀

C z = ln P₀ / P

z = 1 / C ln P₀ / P

Let's calculate

z = 1 / 1.1 10⁻⁵ ln (610/10)

z = 3,737 10⁵ m

4 0

3 years ago