Ba3PO4 is not neutral, it is positive. (NH4)2SO4 is neutral, the charges cancel.
Mg2OH is not neutral, it is positive. LiF2 is not neutral, it is negative. CaOH is not neutral, it is positive. The answer is (NH4)2SO4, correct ions will have a neutral charge.
CH2O. You can reduce 8, 16, and 8 to 1, 2, and 1. You just simplify the numbers. When there is no number after an element, it means that there is one of them.
Answer:
Gravitational force is directly promotional to the mass
of both interacting objects.
Explanation:
More massive objects will attract each other with
a greater gravitional force. So as the mass of the
either objects increases the force of gravitational
attraction between them also increases.
27,586
<h3>
Further explanation</h3>
<u>Given:</u>
A single gold atom has a diameter of 
From a reference, the Rutherford gold foil used in his scattering experiment had a thickness of approximately 
<u>Question:</u>
How many atoms thick were Rutherford's foil?
<u>The Process:</u>
Convert thickness from mm to cm.

The number of atoms is calculated from gold foil thickness divided by the atomic diameter.


Therefore, we get an atomic thickness of 27,586 atoms.
<u>Notes:</u>
- In 1909-1910, Ernest Rutherford with two of his assistants, namely Hans Geiger and Ernest Marsden, conducted a series of experiments to find out more about the arrangement of atoms. They fired at a very thin gold plate with high-energy alpha particles.
- One of their observations is that a small portion of alpha particles are reflected. This greatly surprised Rutherford. The reflected alpha particle must have hit something very dense in the atom. This fact is incompatible with the atomic model proposed by J.J. Thomson where the atoms are described as homogeneous in all parts with electrons and protons evenly distributed.
- In 1911, Rutherford was able to explain the scattering of alpha rays by proposing ideas about atomic nuclei. According to him, most of the mass and positive charge of atoms are concentrated at the center of the atom, hereinafter referred to as the nucleus.
<h3>Learn more</h3>
- The energy density of the stored energy brainly.com/question/9617400
- The theoretical density of platinum which has the FCC crystal structure. brainly.com/question/5048216
- Compound microscope brainly.com/question/4000241
Keywords: if a single gold atom, has a diameter of 2.9 x 10⁻⁸ cm, how many, atoms thick, Rutherford's foil, his scattering experiment