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2 years ago

How was newton's laws used to solve problems on apollo 13 ship Explain in two full paragraphs

Physics

1 answer:

MaRussiya [10]2 years ago

3 0

Answer:

actually ships are made in newtons third law of motion.it states to every action there is equal and opposite reaction. curved is made in downwards to maintain upthrust and to made balance.

actually it prevents ships from drowning and to move with a heavy mass.

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The amount of work done against friction to slide a box in a straight line across a uniform, horizontal floor depends most on th

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Amount of force that is applied to the box

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3 years ago

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Witch scientific tool helps to make distant objects nearer and larger?

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Answer:

magnifying glass

Explanation:

makes objects bigger and smaller / used in science

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3 years ago

Generators use the magnetic field of which of the following to produce an electric current?

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3 years ago

You have a meteorite sample and you decide to use the uranium-235/lead-207 system to date it. After analysis, you find that it h

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Originally there must been

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2 years ago

A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.

Mama L [17]

Answer: $f_{r}$ = 16.49N

Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,

$W_{x}$ = horizontal component of the weight = mgsinФ

$W_{y}$ = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

mgsinФ - $f_{r}$ = ma

where m = mass of object=5kg

a = acceleration= unknown

Ф = angle of inclination = 37°

g = acceleration due to gravity = 9.8 $m/s^{2}$

$f_{r}$ = frictional force = unknown

we need to first get the acceleration before the frictional force which is gotten by using the equation below

$v^{2} = u^{2} + 2aS$

where v = final velocity = 2m/s

u = initial velocity = 0m/s (because the object started from rest)

a= unknown

S= distance covered = length of plane = 5m

$2^{2} = 0^{2} + 2*a*5\\\\4= 10 *a\\\\a = \frac{4}{10} \\a = 0.4m/s^{2}$

we slot in a into the equation below to get frictional force

mgsinФ - $f_{r}$ = ma

3 * 9.8 * sin 37 - $f_{r}$ = 3* 0.4

17.9633 - $f_{r}$ = 1.2

$f_{r}$ = 17.9633 - 1.2

$f_{r}$ = 16.49N

4 0

3 years ago