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Rudiy27
3 years ago
6

Why is sterilising the water rarely used in treating the sewage water?

Chemistry
1 answer:
Marina86 [1]3 years ago
7 0

Answer:

Sterilizing the water rarely used in treating the sewage water is described below in details.

Explanation:

Sterilization is the application of a chemical or physical system to eradicate all microorganisms, concluding comprehensive amounts of bacterial content. Heat treatment is the most relevant approach for the sterilization of waste-water that accommodates large levels of masses. well now sterilizing the water is un-usually practiced in managing the sewage water.

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Greenhouse gases act to __________ temperatures by __________ thermal infrared radiation. Group of answer choices increase; refl
Harlamova29_29 [7]

Greenhouse gases act to <u>increase</u> temperatures by <u>absorbing</u> thermal infrared radiation.

We have already learned that Earth's atmosphere is composed often of nitrogen and oxygen. Those gases are transparent to incoming solar radiation. they may be also transparent to outgoing infrared radiation, which means that they do not take in or emit sun or infrared radiation.

The multiplied quantities of greenhouse gases human sports are adding to the environment have dissatisfied the balance that has been in location for the reason that ceases of the closing ice age, including greater greenhouse gases decreases the amount of infrared radiation energy leaving the atmosphere.

Greenhouse gases inside the ecosystem time and again absorb and re-radiate infrared radiation (warmth). strength radiated from Earth's surface as warmth, or infrared radiation is absorbed and re-radiated by using greenhouse gases, impeding the loss of warmth from our surroundings to area.

Learn more about radiations here brainly.com/question/24469662

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4 0
1 year ago
In 1887, Albert A. Michelson and Edward W. Morley conducted an experiment to measure the speed at which the Earth moves through
vichka [17]
<span> C.The results of the Michelson-Morley experiment did not fit the theory of the luminiferous ether, so the theory had to be rejected. </span>
7 0
3 years ago
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What thype of bond requires the give and take of electrons ?
DedPeter [7]
Ionic bond involves electrostatic attraction between oppositely charged ions.
The ions are atoms that have gained 1 or more electrons and atoms that have lost 1 or more electrons.
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3 years ago
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Please explain to me how to answer no.2 questions
bulgar [2K]

Answer: -

IE 1 for X = 801

Here X is told to be in the third period.

So n = 3 for X.

For 1st ionization energy the expression is

IE1 = 13.6 x Z ^2 / n^2

Where Z =atomic number.

Thus Z =( n^2 x IE 1 / 13.6)^(1/2)

Z = ( 3^2 x 801 / 13.6 )^ (1/2)

= 23

Number of electrons = Z = 23

Nearest noble gas = Argon

Argon atomic number = 18

Number of extra electrons = 23 – 18 = 5

a) Electronic Configuration= [Ar] 3d34s2

We know that more the value of atomic radii, lower the force of attraction on the electrons by the nucleus and thus lower the first ionization energy.

So more the first ionization energy, less is the atomic radius.

X has more IE1 than Y.

b) So the atomic radius of X is lesser than that of Y.

c) After the first ionization, the atom is no longer electrically neutral. There is an extra proton in the atom.

Due to this the remaining electrons are more strongly pulled inside than before ionization. Hence after ionization, the radii of Y decreases.

4 0
3 years ago
Using the Bohr model, determine the energy in joules of the photon produced when an electron in a Li2+ ion moves from the orbit
djverab [1.8K]

Answer:

1.64x10⁻¹⁸ J

Explanation:

By the Bohr model, the electrons surround the nucleus of the atom in shells or levels of energy. Each one has it's energy, and the electron doesn't fall to the nucleus because it can reach another level of energy, and then return to its level.

When the electrons go to another level, it absorbs energy, and then, when return, this energy is released, as a photon (generally as luminous energy). The value of the energy can be calculated by:

E = hc/λ

Where h is the Planck constant (6.626x10⁻³⁴ J.s), c is the light speed (3.00x10⁸ m/s), and λ is the wavelength of the photon.

The wavelength can be calculated by:

1/λ = R*(1/nf² - 1/ni²)

Where R is the Rydberg constant (1.097x10⁷ m⁻¹), nf is the final orbit, and ni the initial orbit. So:

1/λ = 1.097x10⁷ *(1/1² - 1/2²)

1/λ = 8.227x10⁶

λ = 1.215x10⁻⁷ m

So, the energy is:

E = (6.626x10⁻³⁴ * 3.00x10⁸)/(1.215x10⁻⁷)

E = 1.64x10⁻¹⁸ J

3 0
3 years ago
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