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mario62 [17]
3 years ago
7

Which statement describes the valence electrons in metallic bonds? a)They are shared equally between two atoms. b)They are share

d unequally between two atoms. c)They are shared among many atoms. d)They are transferred from one atom to another.
Chemistry
2 answers:
amid [387]3 years ago
7 0
I believe the correct answer from the choices listed above is option C. The statement that describes the valence electrons in metallic bonds would be that they <span>are shared among many atoms. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
harkovskaia [24]3 years ago
4 0

Answer:

c)They are shared among many atoms.

Explanation:

In metals the valence electrons are not localized to a single atom, instead the electron cloud is delocalized and is shared among many metallic cations. Metallic bonds involve the electrostatic force of attraction between the electrons and the metal cation. Metallic bond is different from ionic or covalent bond. In ionic bond there is transfer of electron from the metal to the nonmetal and in covalent bonds electrons are shared between two nonmetals.

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Hey I'm a newbie any help please with this
solniwko [45]
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4 0
4 years ago
Ethyl butyrate, CH3CH2CH2CO2CH2CH3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange
SIZIF [17.4K]

Answer:

A. 10.0 grams of ethyl butyrate would be synthesized.

B. 57.5% was the percent yield.

C. 7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

Explanation:

CH_3CH_2CH_2CO_2H(l)+CH_2CH_3OH(l)+H^+\rightarrow CH_3CH_2CH_2CO_2CH_2CH_3(l)+H_2O(l)

A

Moles of butanoic acid = \frac{7.60 g}{88 g/mol}=0.08636 mol

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

\frac{1}{1}\times 0.08636 mol=0.08636 mol of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 100%

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

100\%=\frac{\text{Experimental yield}}{10.0 g}\times 100

Experimental yield = 10.0 g

10.0 grams of ethyl butyrate would be synthesized.

B

Theoretical yield of ethyl butyrate  = 10.0 g

Experimental yield ethyl butyrate = 5.75 g

Percentage yield of the reaction = ?

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{5.75 g}{10.0 g}\times 100=57.5\%

57.5% was the percent yield.

C

Moles of butanoic acid = \frac{7.60 g}{88 g/mol}=0.08636 mol

According to reaction ,1 mole of butanoic acid gives 1 mol of ethyl butyrate,then 0.08636 mol of butanoic acid will give :

\frac{1}{1}\times 0.08636 mol=0.08636 mol of ethyl butyrate

Mass of 0.08636 moles of ethyl butyrate =

0.08636 mol × 116 g/mol = 10.0 g

Theoretical yield = 10.0 g

Experimental yield = ?

Percentage yield of the reaction = 78.0%

Yield\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

78.0\%=\frac{\text{Experimental yield}}{10.0 g}\times 100

Experimental yield = 7.80 g

7.80 grams of ethyl butyrate would be produced from 7.60 g of butanoic acid.

8 0
3 years ago
Help ASAP pleaseeee thank you
Artyom0805 [142]
The correct answer is B. balance
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3 years ago
How many protons, neutrons, and electrons does gold have? I need to know how many protons, neutrons, and electrons the element g
zhuklara [117]
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neutrons: 118
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3 years ago
How many atoms does 2.0 moles of He represent
Rudiy27

We use the following formula to calculate the number of atoms:

n (mol) = N(number of atoms) / NA

N(He) = n(mol) · NA

N(He) = 2,0 moles · 6.02·1023 = 12.04·1023 atoms

6 0
4 years ago
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