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mario62 [17]
3 years ago
7

Which statement describes the valence electrons in metallic bonds? a)They are shared equally between two atoms. b)They are share

d unequally between two atoms. c)They are shared among many atoms. d)They are transferred from one atom to another.
Chemistry
2 answers:
amid [387]3 years ago
7 0
I believe the correct answer from the choices listed above is option C. The statement that describes the valence electrons in metallic bonds would be that they <span>are shared among many atoms. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
harkovskaia [24]3 years ago
4 0

Answer:

c)They are shared among many atoms.

Explanation:

In metals the valence electrons are not localized to a single atom, instead the electron cloud is delocalized and is shared among many metallic cations. Metallic bonds involve the electrostatic force of attraction between the electrons and the metal cation. Metallic bond is different from ionic or covalent bond. In ionic bond there is transfer of electron from the metal to the nonmetal and in covalent bonds electrons are shared between two nonmetals.

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Can u pls answer 22, 23, 24
natulia [17]

Answer:

22 - b, 23- A, 24- a

Explanation:

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2 years ago
I need help with number two
Komok [63]
The temperature is held constant at (b) and (d). At these points, the substance is changing states. B is changing from solid to liquid and D is changing from liquid to gas
3 0
2 years ago
Calculate the EMF of the following cell at standard conditions (temperature = 25o C, pressure = 1 atmosphere): Ni | Ni2+ | | Cu2
kakasveta [241]

Answer:

a) +0.574 V

b) +0.573V

Explanation:

The EMF is the electromotive force, which is the property of a device that intends to generate electrical current. The EMF of a cell can be calculated by the Nernst equation:

Emf = E° - (0.0592/n)*logQ

Where E° is the standard reduction potential of the cell, n is the number of electrons involved in the reaction, and Q is the reaction quotient ([products]/[reactants]).

In the cell, a redox reaction happens. One substance oxides (lose electrons and become a cation), and the other one reduces (gains electrons and becomes an anion). Each reaction has a reduction potential (E), which indicates how easily is to the reduction happens (as higher E as easy).

For the overall reaction, E° = Ereduction - Eoxidation. To the cell given, Ni is oxidizing, and Cu⁺² is reducing, so, the half-reactions with its E (which can be found at tables), and the overall reaction are:

Ni(s) → Ni⁺² + 2e⁻ E = -0.24 V

Cu⁺² + 2e⁻ → Cu(s) E = +0.337 V

Ni(s) + Cu⁺² → Ni⁺² + Cu(s)

E° = +0.337 - (-0.24)

E° = +0.577 V

As we can see, there're 2 electrons involved in the reaction, so n =2.

The solids don't take place in the Q value, so:

Q = [Ni⁺²]/[Cu⁺²]

a) Q = 0.1/0.08 = 1.25

Emf = 0.577 - (0.0592/2)*log(1.25)

Emf = 0.577 - 0.003

Emf = +0.574 V

b) Q = 0.4/0.3 = 1.33

Emf = 0.577 - (0.0592/2)*log(1.33)

Emf = 0.577 - 0.004

Emf = +0.573 V

3 0
3 years ago
Explain how barometric pressure is measured.
Lisa [10]

Answer:

inches of mercury (inHg or “Hg) or millibars.

6 0
3 years ago
MASS = 10 Kg, Acceleration = 3 m/s/s, Force =
Orlov [11]

Answer:

The force is 30 N

Explanation:

We use the formula F= mx a

F= 10kg x 3m/s2

F= 30kgxm/s2= 30 Newton

7 0
3 years ago
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