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konstantin123 [22]
2 years ago
14

How did astronomers estimate the age of Venus' surface?

Physics
2 answers:
Blababa [14]2 years ago
7 0

Answer:

How did astronomers estimate the age of Venus' surface?

Radiometric dating

Stratigraphy

<u>They counted the craters.</u>

They brought surface samples back to Earth.

<em>Hope</em><em> this</em><em> helps</em>

DiKsa [7]2 years ago
5 0

The answer would be...A: Stratigraphy

Have a good day! :)

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Explain what happens to the pitch of a cell phone ring when the amplitude of a sound wave increases. Justify your reasoning usin
dalvyx [7]
<span>Nothing happens to the pitch of a cell phone ring when the amplitude
of a sound wave increases. 

Pitch and amplitude are both characteristics of a wave, but they're not
connected, and they don't influence each other.</span>
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2 years ago
Which statement best describes the atoms of elements that form compounds by covalent bonding?
k0ka [10]

Answer:

they share electrons between them.

Explanation:

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4 0
3 years ago
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seropon [69]
I think number 1 is incorrect I believe that answer is D. Number 6 I believe would be B. The rest seem to be correct.
4 0
3 years ago
Read 2 more answers
In a two-slit experiment using coherent light, the distance between the slits and the screen is 1.10 m, and the distance between
Paul [167]

Answer:

D) 763 nm

Explanation:

Calculation for the wavelength of light

Using this formula

Wavelength of light=Delta Y*Distance / Length

Where,

Delta Y represent the 2nd order bright fringe

Length represent the distance between both the slits and the screen

Distance represent the Distance between the slits

Let note that cm to m = (4.2) x 10^-2 and mm to m= ( 0.0400x 10^-3)

Now Let plug in the formula

Wavelength of light=[(4.2 x 10^-2m)(0.0400 x 10^-3m) / 2(1.1m)]*10^-7 meters

Wavelength of light=[(0.042m) (0.0004m)/2.2m]*10^-7 meters

Wavelength of light =(0.0000168m/2.2m)*10^-7 meters

Wavelength of light =7.63 *10^-7 meters

Wavelength of light =763 nm

Therefore the Wavelength of light will be 763 nm

3 0
2 years ago
A tennis ball is released from a height of 4.0 m above the floor. After its third bounce off the floor, it reaches a height of 1
diamong [38]

Answer:

The percentage of its mechanical energy does the ball lose with each bounce is 23 %

Explanation:

Given data,

The tennis ball is released from the height, h = 4 m

After the third bounce it reaches height, h' = 183 cm

                                                                       = 1.83 m

The total mechanical energy of the ball is equal to its maximum P.E

                                      E = mgh

                                          = 4 mg

At height h', the P.E becomes

                                      E' = mgh'

                                           = 1.83 mg

The percentage of change in energy the ball retains to its original energy,

                                 \Delta E\%=\frac{1.83mg}{4mg}\times100\%

                                  ΔE % = 45 %

The ball retains only the 45% of its original energy after 3 bounces.

Therefore, the energy retains in each bounce is

                                   ∛ (0.45) = 0.77

The ball retains only the 77% of its original energy.

The energy lost to the floor is,

                                E = 100 - 77

                                   = 23 %

Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %      

5 0
3 years ago
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