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2 years ago

What force types change the direction of motion

2 answers:

7 0

Forces affect how objects move. They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving. Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity. Let’s say an object is moving along a table on earth, suddenly the finite table ends, resulting in the object being present in the air, which means there is no normal contact force N to combat the force by gravity mg, which is why there is an acceleration downwards. This proves as a projectile motion since the direction of motion start changing from horizontal to vertical. Another example is one throwing an object up. It moves up and slows down, reaching its maximum point, leading to it starting to move downwards. This too is a change in motion.

Leno4ka [110]2 years ago

7 0

I believe an unbalanced force.

Unbalanced force is the change in direction of motion.

Here, look at the following definition: If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. An object is said to be acted upon by an unbalanced force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.

You might be interested in

1. Calculate the momentum of a 1,500 kg car traveling at 6 m/s.

ziro4ka [17]

Answer:

1. $9000kgm/s$

2. $258,000kgm/s$

Explanation:

1.Momentum is given as the product of mass by velocity of an object.

Momentum, $p=mv$

m=1,500kh, v=6m/s

$p=1500*6\\p=9000kgm/s$

2.Momentum, $p=mv$

m=7800kg, v=30m/s

$p_1=7800*30\\p_1=234,000kgm/s\\$

new mass=7800+800=8600

As mass is increased, so does the resultant velocity as mass is directly proportional to velocity.

$p_2=8600*30\\p_2=258,000kgm/s$

8 0

3 years ago

55 L of a gas at 25oC has its temperature increased to 35oC. What is its new volume?

ladessa [460]

Answer:

Approximately 56.8 liters.

Assumption: this gas is an ideal gas, and this change in temperature is an isobaric process.

Explanation:

Assume that the gas here acts like an ideal gas. Assume that this process is isobaric (in other words, pressure on the gas stays the same.) By Charles's Law, the volume of an ideal gas is proportional to its absolute temperature when its pressure is constant. In other words

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1}$ ,

where

$V_2$ is the final volume,
$V_1$ is the initial volume,
$T_2$ is the final temperature in degrees Kelvins.
$T_1$ is the initial temperature in degrees Kelvins.

Convert the temperatures to degrees Kelvins:

$T_1 = \rm 25^{\circ}C = (25 + 273.15)\; K = 298.15\; K$ .

$T_2 = \rm 35^{\circ}C = (35 + 273.15)\; K = 308.15\; K$ .

Apply Charles's Law to find the new volume of this gas:

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 55\;L \times \frac{308.15\; K}{298.15\; K} = 56.8\; L$ .

8 0

3 years ago

In what organelle does photosynthesis occur

Fofino [41]

Answer:

chloroplasts

Explanation:

In plants, photosynthesis takes place in chloroplasts, which contain the chlorophyll. Chloroplasts are surrounded by a double membrane and contain a third inner membrane, called the thylakoid membrane, that forms long folds within the organelle.

5 0

3 years ago

A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

VMariaS [17]

Answer:

41.9 g

Explanation:

We can calculate the heat released by the water and the heat absorbed by the steel rod using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in temperature

If we consider the density of water is 1.00 g/mol, the mass of water is 125 g.

According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

cw × mw × ΔTw = -cs × ms × ΔTs

(4.18 J/g.°C) × 125 g × (21.30°C-22.00°C) = -(0.452J/g.°C) × ms × (21.30°C-2.00°C)

ms = 41.9 g

3 0

3 years ago

How many moles in 3.69 x 10^30 molecules of carbon dioxide?

Sedaia [141]

$0.612 \times 10^{7} \text { moles of } \mathrm{CO}_{2}$ are present in $3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}$

<u>Explanation:</u>

It is known that each mole of an element is composed of avagadro's number of molecules. So if we need to determine, we need to divide the number of molecules with the avagadro's number.

So,

$1 mol of element =6.02 \times 10^{23} molecules of element$

As here $3.69 \times 10^{30}$ molecules of carbon di oxide is given. So the moles in it will be

No. of moles of carbon dioxide = $\frac{3.69 \times 10^{30}}{6.02 \times 10^{23}}$

No. of moles = $0.612 \times 10^{7}$ moles of carbon dioxide.

Thus,

$0.612 \times 10^{7}$ of carbon dioxide are present in $3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}$ .

4 0

2 years ago