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Ipatiy [6.2K]
3 years ago
8

A nasa spacecraft measures the rate r of at which atmospheric pressure on mars decreases with altitude. the result at a certain

altitude is: =r0.0421·kpakm−1 convert r to ·jcm−4 .
Physics
2 answers:
Pie3 years ago
4 0
<span>this is simple question of conversion of unit But as we can see here that one is in kpa or kilo pascal which is a unit of pressure while another is in joule which is unit of energy but if we do the dimension matching we could see that 1pa = 1J/m^3 and 0.0421kpa/km=0.0421pa/m now putting above equation as substitution 0.0421pa/m=0.0421J/m^4 100 cm = 1 m putting it we get R= 4.21Ă—10^-10 J/cm^4</span>
Lesechka [4]3 years ago
3 0

Answer:4.21 \times 10^{-10} J/cm^4

1 kPa= 10^3 Pa

1 km=10^5 cm

1kPa/km=0.01 Pa/cm

1kPa/km=10^{-8} J/cm^4

\Rightarrow r= 0.0421 kPa/km= 0.0421 kPa/km \times \frac{10^{-8} J/cm^4}{1 kPa/km}= 0.0421 \times 10^{-8}J/cm^4=4.21 \times 10^{-10} J/cm^4

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a = Δv / t

a = v₂ – v₁ / t ....... (2)

From equation (1), make Δv the subject of the equation.

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Cross multiply

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Considering the options given in question above, t = Δa / v is not a true statement.

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