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pshichka [43]
2 years ago
9

A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming

no frictional forces, what was the initial velocity the fisherman gave the lure when he cast it?
12.34 m/s
28.45 m/s
34.91 m/s
21.29 m/s
Physics
1 answer:
larisa86 [58]2 years ago
5 0

Answer:

did you figure out the answer

Explanation:

??

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Explanation:

Rhythm, Harmony, Timbre, Dynamics, Texture, and Form

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2 years ago
Ceres, Pluto, and Eris are all round in shape and classified as:_________ A) Leftover planetesimals that formed inside the frost
motikmotik

Answer

Ceres, Pluto, and Eris are classified as DWARF PLANET.

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5 0
3 years ago
The particle is an electron. the field slows down the electron without deflecting it. what is the direction of the electric fiel
sammy [17]

The particle is an electron. The field slows down the electron without deflecting it. The direction of the electric field is <u>right.</u>

In physics, the motion of electrically charged particles gives rise to a field called an electric field. It is measured in force per unit charge.

This field applies force on other charged particles.

Particles bearing opposite charges attract each other while particles having similar charges repel each other in the field.

If a positive charge is placed in the field then the field line moves in an outward direction and for a negative charge, the direction of the lines is inward.

If you need to learn more about electric field click here:

brainly.com/question/26199225

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7 0
1 year ago
Tennis balls traveling at greater than 100 mph routinely bounce off tennis rackets. At some sufficiently high speed, however, th
Kipish [7]

Answer:

Probability of tunneling is 10^{- 1.17\times 10^{32}}

Solution:

As per the question:

Velocity of the tennis ball, v = 120 mph = 54 m/s

Mass of the tennis ball, m = 100 g = 0.1 kg

Thickness of the tennis ball, t = 2.0 mm = 2.0\times 10^{- 3}\ m

Max velocity of the tennis ball, v_{m} = 200\ mph = 89 m/s

Now,

The maximum kinetic energy of the tennis ball is given by:

KE = \frac{1}{2}mv_{m}^{2} = \frac{1}{2}\times 0.1\times 89^{2} = 396.05\ J

Kinetic energy of the tennis ball, KE' = \frac{1}{2}mv^{2} = 0.5\times 0.1\times 54^{2} = 154.8\ m/s

Now, the distance the ball can penetrate to is given by:

\eta = \frac{\bar{h}}{\sqrt{2m(KE - KE')}}

\bar{h} = \frac{h}{2\pi} = \frac{6.626\times 10^{- 34}}{2\pi} = 1.0545\times 10^{- 34}\ Js

Thus

\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}

\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}

\eta = 1.52\times 10^{-35}\ m

Now,

We can calculate the tunneling probability as:

P(t) = e^{\frac{- 2t}{\eta}}

P(t) = e^{\frac{- 2\times 2.0\times 10^{- 3}}{1.52\times 10^{-35}}} = e^{-2.63\times 10^{32}}

P(t) = e^{-2.63\times 10^{32}}

Taking log on both the sides:

logP(t) = -2.63\times 10^{32} loge

P(t) = 10^{- 1.17\times 10^{32}}

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3 years ago
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Leni [432]

Answer:

I think hes cool

Explanation:

8 0
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