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Radda [10]
3 years ago
8

How much power is needed to produce 500 joules of work if 20 watts are used?

Physics
2 answers:
soldier1979 [14.2K]3 years ago
8 0
350 produce hope this helps
evablogger [386]3 years ago
6 0
Answer:25 produce
I might be wrong
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What is being transferred as you do work?<br> A. Energy<br> B. Power<br> C. Heat<br> D. Strength
r-ruslan [8.4K]

\huge\bold{\purple{\bold{⚡A. Energy⚡}}}

\huge\underline\mathtt\colorbox{cyan}{Reason:}

When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force 'F' moves an object through a distance 'd'. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.

4 0
3 years ago
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How do streams change as they flow from mountains down to plains? Plz help URGENT I need it today
lisov135 [29]
They start as one stream, then get curvier, then empy into a delta. A delta is a ton of streams of water. It is one, then empties out into a ton of streams.
~Deceptiøn

5 0
3 years ago
How do I solve this problem
PilotLPTM [1.2K]

Answer:

it is light

Explanation:

the arrow that says light is on the glass it must be near from tungsten

5 0
3 years ago
A 200kg bumper car moving 3 m/s collides head on with a 392kg bumper car moving 6m/s. After impact, the larger car continues tra
Maru [420]

Answer:

the final speed of the smaller car is 5.624 m/s

Explanation:

Given;

mass of the small car, m₁ = 200 kg

initial velocity of the small car, u₁ = 3 m/s

mass of the larger car, m₂ = 392 kg

initial velocity of the larger car, u₂ = 6 m/s

final velocity of the larger car, v₂ = 1.6 m/s

let the direction of the larger car be positive

let the direction of the smaller car be negative

Apply the principle of conservation of linear momentum to determine the final speed of the smaller car.

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

200(-3)  +  392(6)  = 200v₁   +  392 x 1.6

-600 + 2352  = 200v₁    +  627.2

1752   =  200v₁     +   627.2

1752  -  627.2     =  200v₁

1124.8  = 200v₁

v₁  =  1124.8/200

v₁ = 5.624 m/s

Therefore, the final speed of the smaller car is 5.624 m/s

7 0
3 years ago
In the desert air, sound travels at 358 meters per second (m/s). In the polar air, sound travels at 330 meters per
Sati [7]

Answer:

The correct option is;

C. The temperature of the air affects the speed of sound

Explanation:

The information given are;

The speed with which sound travels in the desert air = 358 m/s

The speed with which sound travels in the polar air = 330 m/s

The major difference between the desert air and the polar air is that the temperature of the desert air is hotter than the temperature of the air in the polar region. Therefore the speed of sound is affected by the air temperature.

The equation that gives the relationship of the speed of sound in air, v_{air}, to temperature is presented as follows;

v_{air} = 331\frac{m}{s} \times \sqrt{\dfrac{T_K}{273 K} } =  331\frac{m}{s} \times \sqrt{1 + \dfrac{T_{^{\circ}C}}{273 ^{\circ} C} }

Which shows that the speed of sound in air, v_{air}, rises as the temperature of the air rises.

Where;

T_{^{\circ}C} = The temperature of the air in degrees Celsius

T_K = The temperature of the air in degrees Kelvin.

7 0
4 years ago
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