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torisob [31]
3 years ago
6

____ is the most common mineral in the human body.

Chemistry
2 answers:
Brums [2.3K]3 years ago
7 0
Calcium is the most common mineral in the human body.
Hope this helps~
maks197457 [2]3 years ago
5 0

C, calcium. Hope this helps.

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How do you make fried chicken im white and don't know how to season
Tpy6a [65]

Answer:

lol you use batter use flour salt pepper  thats what gives it the fried and crispy taste

Explanation:

4 0
2 years ago
Patient added a 17-g measured dose of polyethylene glycol 3350 (MIRALAX) to 180 mL of water to use as a laxative. If the volume
Sergio [31]

Answer: Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

Specific gravity of mixture = 1.01

Explanation:

The specific gravity of an object or substance is the ratio of the density of that object or substance to that of a reference substance usually water.

<em>Specific gravity = density of substance/density of water</em>

The density of a substance is the ratio of the mass of that substance to is volume.

<em>Density = Mass/volume</em>

Density of water 1.00 g/mL,  

Apparent density of ethylene glycol 3350 = mass/volume

volume of ethylene glycol = volume of mixture - volume of water

volume of ethylene glycol = 195.6 - 180) = 15.6mL

Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL

<em>mass of water =  density of water * volume of water</em>

mass of water = 1.00g/mL * 180mL = 180 g

Mass of solution = mass of substance + mass of water = (17 + 180)g = 197g

Density of mixture = mass of mixture / volume of mixture

Density of mixture = 197 g / 195.6 mL = 1.01 g/mL

specific gravity of mixture = density of mixture / density of water

specific gravity of mixture = 1.01g/mL / 1.00g/mL

specific gravity of mixture = 1.01

8 0
4 years ago
What is the half-life of 20 g of a radioactive sample if 5 g remain after 8 minutes?
Anni [7]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 20 g

m (final mass after time T) = 5 g

x (number of periods elapsed) = ?

P (Half-life) = ? (in minutes)

T (Elapsed time for sample reduction) = 8 minutes

Let's find the number of periods elapsed (x), let us see:

m =  \dfrac{m_o}{2^x}

5 =  \dfrac{20}{2^x}

2^x = \dfrac{20}{5}

2^x = 4

2^x = 2^2

\boxed{x = 2}


Now, let's find the half-life (P) of the radioactive sample, let's see:

T = x*P

8 = 2*P

2\:P = 8

P = \dfrac{8}{2}

\boxed{\boxed{P = 4\:minutes}}\Longleftarrow(Half-Life)\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

5 0
3 years ago
Hi! ❤️ , im looking for some help here. ill give brainliest if able to.
dexar [7]

A student builds a model of a race car. The scale is 1:15. In the scale model, the car is 8 cm tall. How tall is the actual car?

<h2>Answers:</h2>

<h3>A. 120 cm</h3>

#CarryOnLearning

7 0
2 years ago
Why is it possible for star that is no longer in space to still appear to shine?
Kamila [148]
There is a difference in the time we see things from space. There is a delay so we see things after they happen
5 0
3 years ago
Read 2 more answers
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