Answer :
(a) The acceleration of the car is, ![-2m/s^2](https://tex.z-dn.net/?f=-2m%2Fs%5E2)
(b) The distance covered by the car is, 150 m
Explanation :
By the 1st equation of motion,
...........(1)
where,
v = final velocity = 5 m/s
u = initial velocity = 25 m/s
t = time = 10 s
a = acceleration of the car = ?
Now put all the given values in the above equation 1, we get:
![5m/s=25m/s+a\times (10s)](https://tex.z-dn.net/?f=5m%2Fs%3D25m%2Fs%2Ba%5Ctimes%20%2810s%29)
![a=-2m/s^2](https://tex.z-dn.net/?f=a%3D-2m%2Fs%5E2)
The acceleration of the car is, ![-2m/s^2](https://tex.z-dn.net/?f=-2m%2Fs%5E2)
By the 2nd equation of motion,
...........(2)
where,
s = distance covered by the car = ?
u = initial velocity = 25 m/s
t = time = 10 s
a = acceleration of the car = ![-2m/s^2](https://tex.z-dn.net/?f=-2m%2Fs%5E2)
Now put all the given values in the above equation 2, we get:
![s=(25m/s)\times (10s)+\frac{1}{2}\times (-2m/s^2)\times (10s)^2](https://tex.z-dn.net/?f=s%3D%2825m%2Fs%29%5Ctimes%20%2810s%29%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%28-2m%2Fs%5E2%29%5Ctimes%20%2810s%29%5E2)
By solving the term, we get:
![s=150m](https://tex.z-dn.net/?f=s%3D150m)
The distance covered by the car is, 150 m