Answer:
The speed of the water is 14.68 m/s.
Explanation:
Given that,
Time = 30 minutes
Distance = 11.0 m
Pressure = 101.3 kPa
Density of water = 1000 kg/m³
We need to calculate the speed of the water
Using equation of motion
![v^2=u^2+2gs](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2gs)
Where, u = speed of water
g = acceleration due to gravity
h = height
Put the value into the formula
![0=u^2-2\times9.8\times11.0](https://tex.z-dn.net/?f=0%3Du%5E2-2%5Ctimes9.8%5Ctimes11.0)
![u=\sqrt{2\times9.8\times11.0}](https://tex.z-dn.net/?f=u%3D%5Csqrt%7B2%5Ctimes9.8%5Ctimes11.0%7D)
![u=14.68\ m/s](https://tex.z-dn.net/?f=u%3D14.68%5C%20m%2Fs)
Hence, The speed of the water is 14.68 m/s.
Answer:
20.7N
Explanation:
There are many students who can not get answers step by step and on time
So there are a wats up group where you can get help step by step and well explained by the trusted experts.
just join the group
post your questions
get answer
Answer:
lives, forces and motion make things move and stay still. Pushing and pulling are examples of forces that can sped things up or slow things down. There are two types of forces, at a distance force and contact forces..
Answer:3764.282 KPa
Explanation:
Given gusher shoots oil at h=25 m
i.e. the velocity of jet is
v=\sqrt{2gh}[/tex]
v=22.147 m/s
Now the pressure loss in pipe is given by hagen poiseuille equation
![\Delta P=\frac{32L\mu v}{D^2}](https://tex.z-dn.net/?f=%5CDelta%20P%3D%5Cfrac%7B32L%5Cmu%20v%7D%7BD%5E2%7D)
![\Delta P=\frac{32\times 50\times 22.147\times 1}{10^{-2}}](https://tex.z-dn.net/?f=%5CDelta%20P%3D%5Cfrac%7B32%5Ctimes%2050%5Ctimes%2022.147%5Ctimes%201%7D%7B10%5E%7B-2%7D%7D)
![\Delta P=3543.557 KPa](https://tex.z-dn.net/?f=%5CDelta%20P%3D3543.557%20KPa)
For 25 m head in terms of Pressure
![\Delta P_2=\rho \times g\times h=220.725 KPa](https://tex.z-dn.net/?f=%5CDelta%20P_2%3D%5Crho%20%5Ctimes%20g%5Ctimes%20h%3D220.725%20KPa)
Total Pressure=
=3543.557+220.725=3764.282 KPa