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Sergio039 [100]
3 years ago
14

You throw a ball straight up with an initial velocity of 15.0 m/s. It passes a tree branch on the way up at a height of 7.00 m.

How much additional time will pass before the ball passes the tree branch on the way back down?
Physics
1 answer:
Irina18 [472]3 years ago
6 0
I dont know like 1 more second 
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What is the electric potential, i.e. the voltage, 0.30 m from a point charge of 6.4 x 10-C?
Gwar [14]

Answer:

V = 192 kV

Explanation:

Given that,

Charge, q=6.4\times 10^{-6}\ C

Distance, r = 0.3 m

We need to find the electric potential at a distance of 0.3 m from a point charge. The formula for electric potential is given by :

V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6.4\times 10^{-6}}{0.3}\\\\V=192000\ V\\\\V=192\ kV

So, the required electric potential is 192 kV.

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3 years ago
1. Is there a relationship between the volume of water displaced and the total volume of the block that has anything to do with
strojnjashka [21]

Answer:

The volume of the block is equal to the volume of water displaced by the block.

Explanation:

Volume refers to the amount of space occupied by a given object (in this case the block). When an object such as the block is immersed in water, it displaces its own volume of water. This volume of water displaced is equal to the volume of the block. Hence we can write;

Final Volume of water - Initial Volume of water= Water Displaced = Volume of the block

Recall that the density of a body is given by;

Density= mass/volume

If we obtain the volume of the block by measuring the volume of water displaced by the block, then we weigh the block using a weighing balance, we can obtain the density of the block easily from the relationship shown above.

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How does Mercury's close proximity to the sun and thin atmosphere affect its ability to maintain liquid water
alekssr [168]

Answer

A thin atmosphere does not supply much oxygen, and the heat from the sun would evaporate it, because mercury is close to the sun.

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3 years ago
A string that is 3.6 m long is tied between two posts and plucked. The string produces a wave that has a frequency of 320 Hz and
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To solve this problem it is necessary to apply the concepts related to wavelength depending on the frequency and speed. Mathematically, the wavelength can be expressed as

\lambda = \frac{v}{f}

Where,

v = Velocity

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L = 3.6m

v= 192m/s

f= 320Hz

Replacing we have that

\lambda = \frac{192}{320}

\lambda = 0.6m

The total number of 'wavelengths' that will be in the string will be subject to the total length over the size of each of these undulations, that is,

N = \frac{L}{\lambda}

N = \frac{3.6}{0.6}

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Therefore the number of wavelengths of the wave fit on the string is 6.

5 0
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