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Natali5045456 [20]
3 years ago
8

Organism undergo constant chemical changes as they maintain an internal balance known as?

Physics
2 answers:
Alecsey [184]3 years ago
7 0

Answer: Homeostasis

Explanation: In biology, homeostasis is the state of steady internal, physical, and chemical conditions maintained by living systems.

Aleks04 [339]3 years ago
3 0
The answer is homeostasis.
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(33%) Problem 3: Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1100 kg and i
expeople1 [14]

Answer:

The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

Explanation:

Given that,

Mass of first car = 1100 kg

Velocity of first car = 8.5 m/s

Mass of second car = 650 kg

Velocity of second car = 17.5 m/s

Suppose we need to find the final velocity of the cars and direction of the cars.

We need to calculate the velocity of the car in west direction

Using conservation of momentum in west direction

m_{f}v_{f}+m_{s}v_{s}= (m_{f}+m_{s})v_{x}

v_{x}=\dfrac{m_{f}v_{f}+m_{s}v_{s}}{(m_{f}+m_{s})}

Put the value into the formula

v_{x}=\dfrac{1100\times0+650\times17.5}{1100+650}

v_{x}=6.5\ m/s

We need to calculate the velocity of the car in south direction

Using conservation of momentum in south direction

m_{f}v_{f}+m_{s}v_{s}= (m_{f}+m_{s})v_{y}

v_{y}=\dfrac{m_{f}v_{f}+m_{s}v_{s}}{(m_{f}+m_{s})}

Put the value into the formula

v_{y}=\dfrac{1100\times8.5+650\times0}{1100+650}

v_{y}=5.3\ m/s

We need to calculate the final velocity of the cars

Using formula of velocity

v_{eq}=\sqrt{(6.5)^2+(5.3)^2}

v_{eq}=8.38\ m/s

We need to calculate the direction

Using formula of direction

\tan\theta=\dfrac{v_{y}}{v_{x}}

Put the value into the formula

\tan\theta=\dfrac{5.3}{6.5}

\theta=\tan^{-1}(\dfrac{5.3}{6.5})

\theta=39.1^{\circ}

Hence, The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

8 0
3 years ago
Conditions of equilibrium of parallel coplanar forces<br><br><br>​
IRISSAK [1]

Answer:

Bruh............

Explanation:

8 0
3 years ago
Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3​
kobusy [5.1K]

Answer:

When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.

When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.

Explanation:

8 0
3 years ago
When an object of weight w is suspended from the center of a massless string?
igomit [66]
I attached a picture of the diagram associated with this question.

Now,
When we check the vertical components of the tension in the rope, we will find that we have two equal components acting upwards.
These two components support the weight and each of them has a value of TcosΘ

The net force acting on the body is zero.
Fnet=Force of tension acting upwards-Force due to weight acting downwards
0 = 2TcosΘ -W
W = 2TcosΘ
T = W / 2cosΘ

4 0
3 years ago
Read 2 more answers
Two canoeists in identical canoes exert the same effort paddling and hence maintain the same speed relative to the water. One pa
Serga [27]

Answer:

Speed of river is 0.45 m/s

Speed of boat is 2.65 m/s

Explanation:

v_r = Speed of river

v_c = Speed of canoe

v_r+v_c=2.8\ m/s

v_r-v_c=-1.9\ m/s

Adding the equations we get

2v_r=0.9\\\Rightarrow v_r=\frac{0.9}{2}\\\Rightarrow v_r=0.45\ m/s

0.42+v_c=2.8\ m/s\\\Rightarrow v_c=2.8-0.45\\\Rightarrow v_c=2.65\ m/s

Speed of river is 0.45 m/s

Speed of boat is 2.65 m/s

6 0
3 years ago
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