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Mazyrski [523]
4 years ago
13

If you touch the two terminals of a power supply with your two fingertips on opposite hands, the potential difference will produ

ce a current through your torso. The maximum safe current is approximately 5 {\rm mA}.If your hands are completely dry, the resistance of your body from fingertip to fingertip is approximately 500 {\rm k\Omega}. If you accidentally touch both terminals of your 120 {\rm V} household electricity supply with dry fingers, will you receive a dangerous shock?If your hands are moist, your resistance drops to approximately 1 {\rm k\Omega}. If you accidentally touch both terminals of your 120 {\rm V} household supply with moist fingers, will you receive a dangerous shock?
Physics
1 answer:
LiRa [457]4 years ago
7 0

Answer:

Yes the body will receive a dangerous shock in both cases.

Explanation:

Different parts of the body has different resistance. skin has the high resistance as compared to other organs of the body.

Dry skin has high resistance than wet skin this is because water is relatively good conductor of electricity, it adds parallel path to the current flow and hence reduces skin resistance.

Dry hands body has approximately 500 kΩ resistance and if 120 V electricity supply current received will be:

I = V/R= 120/ 500*10^3

I= 0.24 mA

Even the current seems is much lower than the safe zone but this is the case in case of DC voltage in case of AC voltage the body will receive a shock this is because the skin pass more current when the voltage is changing i.e. AC.

Similarly for wet hands body resistance is 1 kΩ. so the current through the body seems to be:

I = 120 / 1000

I = 12 mA

The current is higher than safe zone so the body will receive a dangerous shock.

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Dominik [7]

Answer:

2.47 s

Explanation:

Convert the final velocity to m/s.

  • 40 km/h → 11.1111 m/s

We have the acceleration of the gazelle, 4.5 m/s².

We can assume the gazelle starts at an initial velocity of 0 m/s in order to determine how much time it requires to reach a final velocity of 11.1111 m/s.

We want to find the time t.

Find the constant acceleration equation that contains all four of these variables.

  • v = v₀ + at

Substitute the known values into the equation.

  • 11.1111 = 0 + (4.5)t
  • 11.1111 = 4.5t
  • t = 2.469133333

The Thompson's gazelle requires a time of 2.47 s to reach a speed of 40 km/h (11.1111 m/s).

5 0
3 years ago
A crate resting on a horizontal floor (\muμs = 0.61, \muμk = 0.3 ) has a horizontal force F = 49 Newtons applied to the right. T
Darya [45]

Answer:

a = 7.80 m/s²

Explanation:

given,

μs = 0.61

μk = 0.3

F = 49 N

we know,

F = μs m g

m = \dfrac{F}{\mu_s\ g}

m = \dfrac{49}{0.61 \times 9.81}

m = 8.19\ kg

now when the block start moving

F - F_k = F_{net}

F - F_k = ma

a = \dfrac{F}{m}-\dfrac{F_k}{m}

a = \dfrac{F}{m}-\dfrac{\mu_k m g}{m}

a = \dfrac{88}{8.19}-0.3\times 9.8

a = 7.80 m/s²

3 0
4 years ago
What is the magnetic force (in newtons) on a particle traveling in a 1.5 T magnetic field if q = 7.5 microcoulombs and v = 1.75
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Given:

B(Magnetic field): 1.5 T                                                                                

q=  7.5 microcoulombs                                                                                

v= 1.75 x 10 ∧6 m/s                                                                                    

The angle ∅ between B and v is 45 °.                                                    

Now we know that F= qvB sin ∅

Substituting these values we get:

F= 7.5 x 10∧-6 x 1.75 x 10∧6 x 1.5 x sin 45                                                

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3 0
3 years ago
How much electrical potential energy is stored in a capacitor that has 8.0 × 10-10 C of charge on each plate and a potential dif
arsen [322]
THere is a standard relationship that gives this result where the capacity of the capacitor is used:
E=1/2* \frac{Q^2}{C}.
We know though that Q/c=V and thus we can use the relationship:
E=Q*V/2 where we have just substituted in. If we also take into account that Q=VC, we can also get that E=V^2*C/2.
We are given the charge and the potential, so the best expression to use is the middle one.
Substituting, we get that E=1/2*8*10^(-10)*20=8*10^(-9).

The answer is B
8 0
3 years ago
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mr Goodwill [35]

Answer:

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T= 95 K

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m = 28.6 g

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P=Pressure , V=Volume ,n=Moles,T= Temperature ,R=gas constant

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1.6 x 4.87  = n x 0.08206 x 95

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n=\dfrac{m}{M}

M=Molar mass

n=\dfrac{m}{M}

0.99=\dfrac{28.6}{M}

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3 0
3 years ago
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