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alekssr [168]
3 years ago
9

Which units could NOT be used to measure the acceleration of an object?

Chemistry
1 answer:
vodka [1.7K]3 years ago
4 0
Kg should not be used to measure the acceleration of an object.
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One example of matter is​
zaharov [31]

One example of matter could be <em>Light.</em>

6 0
3 years ago
Read 2 more answers
What will be the volume of a gas sample at 358 K if its volume at 255 K is 7.4 L?
Jobisdone [24]

Answer:

10.4 L

Explanation:

V1/T1=V2/T2

V2= (V1*T2)/T1

V2= (7.4L * 358K)/255K

V2=10.4 L

4 0
3 years ago
2. How much force will this car experience if it collides with a wall and the collision lasts for
Pepsi [2]

The momentum of the body is 12 m/s.

<h3>What is momentum?</h3>

Momentum is the product of the mass of a body and velocity. According to Newton's second law, the rate  of change of momentum is equal to the impressed force.

The details required to answer the first two questions are missing hence we can't answer those questions. For the last question;

p = mv

m = mass

v = velocity

p = momentum

v = p/m

v =  72,000 kgm/s/6,000 kg

v = 12 m/s

Learn more about momentum: brainly.com/question/904448

6 0
2 years ago
What is the conjugate acid of HCO3- ?OH-H2CO3CO32-H2OH3O+
adell [148]

<u>Answer:</u> The conjugate acid of HCO_3^- is H_2CO_3

<u>Explanation:</u>

According to the Bronsted-Lowry conjugate acid-base theory:

  • An acid is defined as a substance which looses donates protons and thus forming conjugate base.
  • A base is defined as a substance which accepts protons and thus forming conjugate acid.

To form a conjugate acid of HCO_3^-, this compound will accept one proton to form H_2CO_3

The chemical equation for the formation of conjugate acid follows:

HCO_3^-+H^+\rightarrow H_2CO_3

The conjugate acid formed is named as carbonic acid.

Hence, the conjugate acid of HCO_3^- is H_2CO_3

5 0
3 years ago
For the reaction 6 Li + N2 → 2 Li3N , what is the maximum amount of Li3N (34.8297 g/mol) which could be formed from 14.18 mol (6
Yuki888 [10]
Moles Li = 3.50 g / 6.941 g/mol= 0.504
the ratio between Li and N2 is 6 : 1
moles N2 required = 0.504 /6=0.0840
we have 3.50 g / 28.0134 g/mol=0.125 moles of N2 so N2 is in excess
the ratio between Li and Li3N is 6 : 2
moles Li3N = 0.504 x 2 /6=0.168
mass Li3N = 0.168 mol x 34.8297 g/mol=5.85 g
4 0
3 years ago
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