All categories

3 years ago

Which of the following places would probably have a higher humidity?

Physics

2 answers:

erma4kov [3.2K]3 years ago

8 0

I believe it would be a town near the ocean.

aev [14]3 years ago

3 0

Just think of Florida we have almost 100% humidity all the time and we are surrounded by ocean so A is your answer

You might be interested in

Consider two rocks with masses of 1 and 10 kilograms. What is the relation between their inertias? Between their masses? Between

FinnZ [79.3K]

The greater mass the object has the greater its inertia would be. As inertia becomes greater, the same happens with the force which is needed stop motion. Linear motion and rotational motion are quite different, because the first one depends only on mass while the second embraces mass, size and shape of an object. According to the information I shared, one will not be able to stop 10 kg mass due to far greater inertia than object of 1kg mass.

Hope you will find it helpful.

7 0

3 years ago

Calculate the unit cell edge length for an 79 wt% Ag- 21 wt% Pd alloy. All of the palladium is in solid solution, and the crysta

ankoles [38]

Answer:

The edge length is 0.4036 nm

Solution:

As per the question:

Density of Ag, $\rho = 10.49 g/cm^{3}$

Density of Pd, $\rho = 12.02 g/cm^{3}$

Atomic weight of Ag, A = 107.87 g/mol

Atomic weight of Pd, A' = 106.4 g/mol

Now,

The average density, $\rho_{a} = \frac{n A_{avg}} {V_{c}\times N_{A}}$

where

$V_{c} = a^{3}$ = Volume of crystal lattice

a = edge length

n = 4 = no. of atoms in FCC

Therefore,

$\rho_{a} = = \frac{n A_{avg}} {V_{c}\times N_{A}}$

Therefore, the length of the unit cell is given as:

$a = (\frac{nA_{avg}}{\rho_{a}\times N_{a}})^{1/3}$ (1)

Average atomic weight is given as:

$A_{avg} = \frac{100}{\frac{C_{Ag}}{A_{Ag}} + \frac{C_{Pd}}{A_{Pd}}}$

where

$C_{Ag}$ = 79 %

$A_{Ag}$ = 107

$C_{Pd}$ = 21%

$A_{Pd}$ = 106

Therefore,

$A_{avg} = \frac{100}{\frac{79}{107} + \frac{21}{106}} = 106.78$

In the similar way, average density is given as:

$\rho_{a} = \frac{100}{\frac{C_{Ag}}{\rho_{Ag}} + \frac{C_{Pd}}{\rho_{Pd}}}$

$\rho_{a} = \frac{100}{\frac{79}{10.49} + \frac{21}{12.02}} = 10.78 g/cm^{3}$

Therefore, edge length is given by eqn (1) as:

$a = (\frac{4\times 106.78}{10.78\times 6.023 X 10^23})^{1/3} = 4.036\times 10^{- 8} cm = 0.4036\times 10^{- 9} m = 0.4036 nm$

5 0

3 years ago

A cell phone company relies on which kind of waves in order to provide service for its customers?

Tanzania [10]

Radio waves are what cell phone company rely on

4 0

3 years ago

Read 2 more answers

Eddie and Val observed the picture of an athlete running in a race.

dedylja [7]

Answer:

Your answer would be C Hope this helps

8 0

3 years ago

Which of the following objects cannot make a shadow? Broken piece of glass from a window/wooden pane of the same window? Explain

Lorico [155]

Answer:

broken pieces of glass from a window can't form a shadow.

Explanation:

the reason is that shadow is formed only when light rays hits an opaque object, which doesn't let light to pass through it, but glass is a transparent object, hence light rays passes through it forming no shadow..

i hope it helped....

4 0

3 years ago