What is the velocity of a 0.8kg ball that has a momentum of 3 kg*m/s?
1 answer:
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Answer:
v_f = 10.85 m/s
Explanation:
We will apply the law of conservation of momentum here:
where,
m₁ = mass of roller skater = 47 kg
m₂ = mass of bag = 6 kg
v_1i = initial speed of roller skater = 12 m/s
v_2i = initial speed of the bag = 0 m/s
v_1f = final speed of the roller skater = ?
v_2f = final speed of the bag = ?
Both the bag and the skater will have same speed at the end because kater is carrying the bag:
v_1f = v_2f = v_f
Therefore, the equation will become:
<u>v_f = 10.85 m/s</u>