Hello,
y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)
Answer: -5 < x + 1 < 3
Step-by-step explanation:
Let x be the number.
-5 < x + 1 < 3
Answer:
y = 84
Step-by-step explanation:
1) add 3 to both sides of your equation to cancel out the -3
end up with: (1/3)y + 14 = (1/2)y
2) multiply both sides of your equation by 2 to cancel out the (1/2)
end up with: (2/3)y + 28 = y
3) subtract (2/3)y from both sides of the equation to cancel out the positive (2/3)y
end up with: 28 = (1/3)y
4) multiply both sides of the equation by 3 to cancel out the (1/3)
end up with: 84 = y